日期:2014-05-16  浏览次数:20617 次

并发,阻塞与非阻塞的问题
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请问这是并发的么?阻塞与非阻塞应该怎么处理。

我需要一个并发非阻塞式的,请问如何实现

谢谢
C/C++ code
//NTP_send.c

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/wait.h>
#include <sys/socket.h>
#include <sys/types.h>
#include <sys/time.h>
#include <netinet/in.h>
#include <netdb.h>
#include <unistd.h>
#include <arpa/inet.h>
#include <sys/ioctl.h>
#include<pthread.h>

#define  int8      char
#define  uint8     unsigned char
#define  uint32    unsigned int
#define  ulong32   unsigned long
#define  long32    long
#define  int32     int
#define  long64    long long

//3600s*24h*(365days*70years+17days)
#define  From00to70 0x83aa7e80U

#define  NTPSVR            "192.168.2.8"        //MY server
#define  LOCAL              "192.168.2.109"
#define  LOCALPORT       8000
#define  NTPPORT           123

typedef struct NTPPACKET
{
  uint8     li_vn_mode;
  uint8     stratum;
  uint8     poll;
  uint8     precision;                                         //有符号整数表示本地时钟精确度
  ulong32   root_delay;                                   //到达服务器的一次往返的总延时,是15到16位有符号的定点小数
  ulong32   root_dispersion;                           // 到达服务器的一次标准误差,是15-16位的无符号的定点小数
  int8      ref_id[4];
  ulong32   reftimestamphigh;                      //本地时钟最后被设定或校正的时间T4
  ulong32   reftimestamplow;
  ulong32   oritimestamphigh;                //向服务器请求分离客户机的时间戳,采用64位时标格式T1
  ulong32   oritimestamplow;
  ulong32   recvtimestamphigh;             //向服务器请求到客户机的时间戳,采用64位时标格式T2
  ulong32   recvtimestamplow;
  ulong32   trantimestamphigh;           //向客户机答复分离服务器的时间戳,采用64位时标格式T3,用T3来校正本地时间 
  ulong32   trantimestamplow;
}NTPPacket;

NTPPacket  ntppack,newpack;

//定义为long64,解决32位数的符号位问题
long64   firsttimestamp,finaltimestamp;
long64   diftime,delaytime;

void NTP_Init()
{
  bzero(&ntppack,sizeof(ntppack));
  ntppack.li_vn_mode=0x1b;//0|(3<<2)|(3<<5);
  //获取初始时间戳T1
  firsttimestamp="From00to70"+time(NULL);//-8*3600;
  ntppack.oritimestamphigh=htonl(firsttimestamp);
}

  fd_set  inset1;
  int32  sockfd;
  struct timeval tv,tv1;
  struct timezone tz;
  struct sockaddr_in addr,local_addr;   
  pthread_t tidA,tidB;
  
#define  capacity  2  //定义线程的数量
#define MAXORDER 10
 
#define           timer                       5000                   //每970 us 发个包,计划是1000 us 发一次,考虑到了网络延时30 us
int                 counter                 =      0;                  //所以完全发完应该是1 s
int                 tmp                       =      0;

int                 fd[2];
#define          maxpkt                       100                  //一次发包量
int                 tid_capacity           =     0;                   //第几个线程
char               order[MAXORDER];

int                 rec_maxpkt;                          //接收总量
int                 rec_pkt                 =     0;           //接收计数
 rec_maxpkt=maxpkt*capacity;  //计划接收量    
 
pid_t pid;
pthread_mutex_t ntppack_mutex = PTHREAD_MUTEX_INITIALIZER;//init pthread
pthread_mutex_t newpack_mutex = PTHREAD_MUTEX_INITIALIZER;//init pthread

//用于接收服务器返回的请求,如果接收数与发送的包相同则
//打印结果,否则接收等待
void *recv_pkt(void *);

void *recv_pkt(void *vptr)
{
  int num=0;
  float  rec_ppkt=0;

  while(recv(sockfd,&newpack,sizeof(newpack),0) >0 )
     { 
   
              
       //printf("In revc ok\n");
       pthread_mutex_trylock(&newpack_mutex);
    
    rec_pkt++;

      printf("\n Packets have been  receive %d \n",rec_pkt);
    pthread_mutex_unlock(&newpack_mutex);

    //printf("rec_maxpkt =%d\n",rec_maxpkt);
    //rec_ppkt=(float)(rec_pkt)/(float)(rec_maxpkt);
    //printf("receive percent = %f   %\n",rec_ppkt*100);
    //printf("lost packets = %d \n",rec_maxpkt-rec_pkt);
    //printf("lost percent = %f  % \n",(1-r