日期:2014-05-16  浏览次数:20792 次

求助Linux Hrtimer高精度定时器问题
C/C++ code

#include <linux/kernel.h>
#include <linux/init.h>
#include <linux/module.h>
#include <linux/fs.h>
#include <linux/netdevice.h>
#include <linux/pci.h>
#include <linux/device.h>
#include <linux/time.h>
#include <linux/skbuff.h>
#include <linux/jiffies.h>
#include <linux/interrupt.h>
#include <linux/hrtimer.h>
#include <linux/ktime.h>
#include <asm/irq.h>

MODULE_DESCRIPTION("Just for hrtimer test");
MODULE_AUTHOR("summon (*********@163.com)");
MODULE_LICENSE("GPL");

#define DyS_HRTIMER_US_TO_NS(x)   (x)*1000
static struct hrtimer hrtimer_for_test;

unsigned long g_hr_times = 0;
enum hrtimer_restart hrtimer_callback_func(struct hrtimer *p_timer)
{
    g_hr_times++;
    if (net_ratelimit())
    {
       printk(KERN_DEBUG "The function hrtimer_callback_func, times is %d\n", g_hr_times);
    }    
    return HRTIMER_RESTART;
}

static int hrtimer_init_module(void)
{
    printk( KERN_DEBUG "Module hrtimer_init_module init\n" );  
    ktime_t ktime;
    unsigned long delay_in_ns = DyS_HRTIMER_US_TO_NS(250);
            
    ktime = ktime_set(1,delay_in_ns);
        
    hrtimer_init(&hrtimer_for_test,CLOCK_MONOTONIC,HRTIMER_MODE_REL);
    
    hrtimer_for_test.function = hrtimer_callback_func;
    hrtimer_start(&hrtimer_for_test,ktime,HRTIMER_MODE_REL);
    return 0;
}

static void hrtimer_exit_module(void)
{
    printk( KERN_DEBUG "Module hrtimer_exit_module exit\n" );    
}

module_init(hrtimer_init_module);
module_exit(hrtimer_exit_module);



一个测试程序,最后结果是每秒钟打印1千万次左右,总之不是我想要的1+250us的。
哪位用过的同学告诉一声,万分感谢哈,google过了,不好使


------解决方案--------------------
enum hrtimer_restart hrtimer_callback_func(struct hrtimer *p_timer)
{
g_hr_times++;
if (net_ratelimit())
{
printk(KERN_DEBUG "The function hrtimer_callback_func, times is %d\n", g_hr_times);

hrtimer_for_test.expires=ktime_add_ns(hrtimer_for_test.expires,(u64)(1*1E9+250*1000);
return HRTIMER_RESTART;
}

在定时器重启前楼主没有更新定时器,所以直接返回HRTIMER_RESTART的后果就是又立即直接调用hrtimer_callback_func函数