SQL查询结果连接的有关问题！
日期：2014-05-17 浏览次数：20660 次
SQL查询结果连接的问题！！！！！
select * from
(select CustomerName,c.CustomerID,count(*) as Boys
from tb_masEmPersonalInfo b join tb_masEmployeeEmployer a
on b.EmpersonalInfoID=a.EmpersonalInfoID
join tb_masCustomer c on a.CustomerID=c.CustomerID
where b.GenderID=1 and a.EwStatus in ('A','N')
group by c.CustomerName,c.CustomerID) Boys
查询结果的列为 CustomerName,CustomerID,Boys
select *from
(select CustomerName,c.CustomerID,count(*) as Girls
from tb_masEmPersonalInfo b join tb_masEmployeeEmployer a
on b.EmPersonalInfoID=a.EmPersonalInfoID
join tb_masCustomer c on a.CustomerID=c.CustomerID
where b.GenderID=2 and a.EwStatus in ('A','N')
group by CustomerName,c.CustomerID) Girls
查询结果的列为 CustomerName,CustomerID,Girls
这两个查询结果连接在一张表里.需要实现的结果为
查询结果的列为 CustomerName,CustomerID,Boys，Girls
------解决方案--------------------
select * from
(select CustomerName,c.CustomerID,count(*) as Boys
from tb_masEmPersonalInfo b join tb_masEmployeeEmployer a
on b.EmpersonalInfoID=a.EmpersonalInfoID
join tb_masCustomer c on a.CustomerID=c.CustomerID
where b.GenderID=1 and a.EwStatus in ('A','N')
group by c.CustomerName,c.CustomerID) Boys
查询结果的列为 CustomerName,CustomerID,Boys
select *from
(select CustomerName,c.CustomerID,count(*) as Girls
from tb_masEmPersonalInfo b join tb_masEmployeeEmployer a
on b.EmPersonalInfoID=a.EmPersonalInfoID
join tb_masCustomer c on a.CustomerID=c.CustomerID
where b.GenderID=2 and a.EwStatus in ('A','N')
group by CustomerName,c.CustomerID) Girls
查询结果的列为 CustomerName,CustomerID,Girls
这两个查询结果连接在一张表里.需要实现的结果为
查询结果的列为 CustomerName,CustomerID,Boys，Girls
------解决方案--------------------
- SQL code
select CustomerName,c.CustomerID
,Sum(case when b.GenderID=1 then 1 else 0 end) as Boys
,Sum(case when b.GenderID=2 then 1 else 0 end) as Boys
from tb_masEmPersonalInfo b join tb_masEmployeeEmployer a
on b.EmpersonalInfoID=a.EmpersonalInfoID
join tb_masCustomer c on a.CustomerID=c.CustomerID
where a.EwStatus in ('A','N')
group by c.CustomerName,c.CustomerID
------解决方案--------------------
- SQL code
select * from
(select CustomerName,c.CustomerID,sum(case when b.GenderID=1 then 1 else 0 end ) as Boys,sum(case when b.GenderID=2 then 1 else 0 end ) as Girls,
from tb_masEmPersonalInfo b join tb_masEmployeeEmployer a
on b.EmpersonalInfoID=a.EmpersonalInfoID
join tb_masCustomer c on a.CustomerID=c.CustomerID
where a.EwStatus in ('A','N')
group by c.CustomerName,c.CustomerID)
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