日期:2014-05-18 浏览次数:20600 次
select b.sname,c.sname as csname,a.qty,a.label
from tb2 a join tb1 b on a.scode = b.scode
join tb1 c on a.scode_dist = c.scode
------解决方案--------------------
select b.sname,c.sname,a.qty, a.label from tb2 a left join tb1 b on a.scode =b.scode
left join tb1 c on a.scode_dist =c.scode
------解决方案--------------------
select
b.sname,c.sname as csname,a.qty,a.label
from
tb2 a
full join
tb1 b
on
a.scode = b.scode
full join
tb1 c
on
a.scode_dist = c.scode