日期:2014-05-18 浏览次数:20526 次
SET IDENTITY_INSERT A ON
------解决方案--------------------
insert into A(code)
select code
from B
where not exists
(
select 1 from A
where A.code = B.code
)
--id为自增列,不允许有重复值出现,如果要允许的话,可以打开开关
set identity_insert table_name on
insert into A
(
id,
code
)
select
id,
code
from B
where not exists
(
select 1 from A
where A.code = B.code
)
set identity_insert table_name off
------解决方案--------------------
你的猜测的 对的,把 * 换成具体的字段(和 A表中的字段对应即可)