日期:2014-05-18 浏览次数:20792 次
CREATE TABLE TABLE1
(
Id INT,
Name VARCHAR(100),
Effdate DATETIME
)
GO
INSERT INTO TABLE1
SELECT 1,'aaa','2012-01-01' UNION
SELECT 1,'aaa','2012-03-10' UNION
SELECT 1,'aaa','2012-05-01' UNION
SELECT 2,'bbb','2012-02-01' UNION
SELECT 2,'bbb','2012-04-01'
CREATE TABLE table2
( id INT,
searchdate DATETIME)
GO
INSERT INTO Table2
SELECT 1,'2012-02-02' UNION
SELECT 1,'2012-03-20' UNION
SELECT 2,'2012-03-02'
WITH TableA AS
(SELECT B.Id,searchdate,name,Effdate,DATEDIFF(DAY,Effdate,searchdate) AS Diff
FROM TABLE1 AS A,Table2 AS B
WHERE A.id = B.Id AND DATEDIFF(DAY,Effdate,searchdate) > 0)
SELECT Id,searchdate,name,Effdate
FROM TableA AS A
WHERE Diff <= ALL(SELECT Diff FROM TableA AS B WHERE A.Id = B.Id AND A.Effdate = B.Effdate)
Id searchdate name Effdate
1 2012-02-02 00:00:00.000 aaa 2012-01-01 00:00:00.000
1 2012-03-20 00:00:00.000 aaa 2012-03-10 00:00:00.000
2 2012-03-02 00:00:00.000 bbb 2012-02-01 00:00:00.000
------解决方案--------------------
select a.id,b.searchdate,a.name,a.effdate from table1 a left outer join table2 b on a.id=b.id where not exists
(select 1 from table1 ,table2 where abs(datediff(dd,effdate,b.searchdate))<abs(datediff(dd,a.effdate,b.searchdate)))