日期:2014-05-18 浏览次数:20816 次
select right('http://xxx.xxxxx.com.cn/SZ374.html',charindex('/',REVERSE('http://xxx.xxxxx.com.cn/SZ374.html'))-1)
------解决方案--------------------
declare @a varchar(300)
set @a='http://xxx.xxxxx.com.cn/SZ374.html'
select right(@a,charindex('/',REVERSE(@a))-1)
go
declare @a varchar(300)
set @a='http://xxx.xxxxx.rytryrtcom.cn/SZtryrt374.html'
select right(@a,charindex('/',REVERSE(@a))-1)
------解决方案--------------------
declare @table table (deptcode varchar(34))
insert into @table
select 'http://xxx.xxxxx.com.cn/SZ374.html' union all
select 'http://xxx.xxxxx.com.cn/SZ373.html' union all
select 'http://xxx.xxxxx.com.cn/abd44.html' union all
select 'http://xxx.xxxxx.com.cn/tsss.html'
SELECT
SUBSTRING(deptcode,LEN(deptcode)-CHARINDEX('/',REVERSE(deptcode))+2,
CHARINDEX('/',REVERSE(deptcode))-CHARINDEX('.',REVERSE(deptcode))-1) AS newcol
from @table
/*
newcol
----------------------------------
SZ374
SZ373
abd44
tsss
*/
------解决方案--------------------
mysql> use c1
Database changed
mysql> select * from a;
+----+-------------------------------------------------+
| id | Talent |
+----+-------------------------------------------------+
| 1 | http://xxx.xxxxx.com.cn/SZ374.html |
| 2 | http://xxx.xxxxx.com.cn/SZ374121212.html |
| 3 | http://xxx.xxx.com.cn/SZ3741212121312.html |
| 4 | http://xxx.xxxxxxxx.com.cn/SZ3741212121312.html |
+----+-------------------------------------------------+
4 rows in set (0.00 sec)
mysql> select Mid(talent,instr(talent,'com.cn/')+7,instr(talent,'.html')-instr(t
alent,'com.cn/')-7) from a;
+-------------------------------------------
--------+
| Mid(talent,instr(talent,'com.cn/')+7,instr(talent,'.html')-instr(talent,'com.c
n/')-7) |
+-------------------------------------------
--------+
| SZ374
|
| SZ374121212
|
| SZ3741212121312
|
| SZ3741212121312
|
+-------------------------------------------
--------+
4 rows in set (0.00 sec)
mysql>
------解决方案--------------------
declare @a varchar(300)
set @a='http://xxx.xxxxx.rytryrtcom.cn/SZ374.html'
select left(right(@a,charindex('/',REVERSE(@a))-1),charindex('.',right(@a,charindex('/',REVERSE(@a))-1))-1)
------解决方案--------------------
select parsename(right('http://xxx.xxxxx.com.cn/SZ374.html',PATINDEX ('%/%', REVERSE('http://xxx.xxxxx.com.cn/SZ374.html'))-1),2)
------解决方案--------------------
select parsename(right('http://xxx.xxxxx.com.cn/SZ374.html',charindex ('/', REVERSE('http://xxx.xxxxx.com.cn/SZ374.html'))-1),2)
------解决方案--------------------
同学,楼上的都是标准答案啊:
SELECT newrow =
SUBSTRING(deptcode,LEN(deptcode)-CHARINDEX('/',REVERSE(deptcode))+2,
CHARINDEX('/',REVERSE(deptcode))-CHARINDEX('.',REVERSE(deptcode))-1)
FROM table_name