日期:2014-05-18 浏览次数:20550 次
select * from DataTest t where not exists(select 1 from DataTest where tid=t.tid and dataline>t.dateline)
------解决方案--------------------
create table DataTest
(
TID int null,
FID int null,
DateLine datetime null
)
Insert into DataTest(TID,FID,DateLine) values('1','5','2008-02-21 09:03:00')
Insert into DataTest(TID,FID,DateLine) values('1','6','2008-02-22 09:03:00')
Insert into DataTest(TID,FID,DateLine) values('2','3','2008-06-21 09:03:00')
Insert into DataTest(TID,FID,DateLine) values('2','6','2008-02-25 09:03:00')
Insert into DataTest(TID,FID,DateLine) values('3','8','2008-02-29 09:03:00')
Insert into DataTest(TID,FID,DateLine) values('3','1','2008-05-21 09:03:00')
select * from DataTest t
where DateLine=(select max(DateLine) from DataTest where TID=t.TID)
order by TID
/*
TID FID DateLine
----------- ----------- -----------------------
1 6 2008-02-22 09:03:00.000
2 3 2008-06-21 09:03:00.000
3 1 2008-05-21 09:03:00.000
*/
------解决方案--------------------
--取大小值
/******************************************************************************************************************************************************
Name相同ID最小或最大的记录
整理人:中国风(Roy)
日期:2008.06.06
******************************************************************************************************************************************************/
--> --> (Roy)生成測試數據
if not object_id('Tempdb..#T') is null
drop table #T
Go
Create table #T([ID] int,[Name] nvarchar(1),[Memo] nvarchar(2))
Insert #T
select 1,N'A',N'A1' union all
select 2,N'A',N'A2' union all
select 3,N'A',N'A3' union all
select 4,N'B',N'B1' union all
select 5,N'B',N'B2'
Go
--1、Name相同ID最小的记录(推荐用1,2,3),方法3在SQl05时,效率高于1、2
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID<a.ID)
方法2:
select a.* from #T a join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID
方法3:
select * from #T a where ID=(select min(ID) from #T where Name=a.Name)
方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID>=b.ID group by a.ID,a.Name,a.Memo having count(1)=1
方法5:
select * from #T a group by ID,Name,Memo having ID=(select min(ID)from #T where Name=a.Name)
方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)=0
方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID)
方法8:
select * from #T a where ID!>all(select ID from #T where Name=a.Name)
方法9:
select * from #T a where ID in(select min(ID) from #T group by Name)
--SQL2005:
方法