日期:2014-05-18 浏览次数:20638 次
SELECT
substring(name,1,charindex('-',name)-1) as name,SUM(count) as count AS count
FROM
(SELECT
id1 as Name,
count(id1) as count
FROM table)A
GROUP BY Name
------解决方案--------------------
select left(Name,charindex('-',Name)-1),sum(count) from
group by left(Name,charindex('-',Name)-1)