--想不出什么好方法了，输入起始时间和结束时间
with recordInfo(id,name,recorddate,workhours) as 
(
select 1,'sa',to_date(20120610,'yyyymmdd'),8.00 from dual
union
select 2,'sa',to_date(20120611,'yyyymmdd'),8.00 from dual
union
select 3,'root',to_date(20120611,'yyyymmdd'),9.00 from dual
union
select 4,'root',to_date(20120614,'yyyymmdd'),7.00 from dual
union
select 5,'admin',to_date(20120615,'yyyymmdd'),6.00 from dual
union
select 6,'sa',to_date(20120610,'yyyymmdd'),3.00 from dual
)
select  s.name ,s.dat , nvl(sum(rec2.workhours),0)
  from 
       (select distinct (rec.name) as name, t.dat
          from recordInfo rec,
               (select to_date(replace('&&begin_dat', '-'), 'yyyymmdd') +
                       level - 1 as dat
                  from dual
                connect by level <=
                           (to_date(replace('&&end_dat', '-'), 'yyyymmdd') -
                           to_date(replace('&&begin_dat', '-'), 'yyyymmdd')) + 1
                ) t) s left join recordInfo rec2 on (s.name = rec2.name and trunc(s.dat)  = trunc(rec2.recorddate))
            group by s.name , s.dat
            order by s.name , s.dat 
/


sys@ORCL> /
Enter value for begin_dat: 20120610
old  19:                (select to_date(replace('&&begin_dat', '-'), 'yyyymmdd') +
new  19:                (select to_date(replace('20120610', '-'), 'yyyymmdd') +
Enter value for end_dat: 20120615
old  23:                            (to_date(replace('&&end_dat', '-'), 'yyyymmdd') -
new  23:                            (to_date(replace('20120615', '-'), 'yyyymmdd') -
old  24:                            to_date(replace('&&begin_dat', '-'), 'yyyymmdd')) + 1
new  24:                            to_date(replace('20120610', '-'), 'yyyymmdd')) + 1


NAME  DAT        NVL(SUM(REC2.WORKHOURS),0)
----- ---------- --------------------------
admin 2012-06-10                          0
admin 2012-06-11                          0
admin 2012-06-12                          0
admin 2012-06-13                          0
admin 2012-06-14                          0
admin 2012-06-15                          6
root  2012-06-10                          0
root  2012-06-11                          9
root  2012-06-12                          0
root  2012-06-13                          0
root  2012-06-14                          7
root  2012-06-15                          0
sa    2012-06-10                         11
sa    2012-06-11                          8
sa    2012-06-12                          0
sa    2012-06-13                          0
sa    2012-06-14                          0
sa    2012-06-15                          0

------解决方案--------------------

貌似是写复杂了点  还没怎么想  应该还有简单的吧 大概就这思路了

SQL code

select t3.name,t3.r_d