日期:2014-05-16 浏览次数:20978 次
create table TEST
(
ID VARCHAR2(5) ,
MONEY NUMBER,
STATE VARCHAR2(8),
RIQI VARCHAR2(10),
XIAOZU VARCHAR2(10)
)
insert into test (ID, MONEY, STATE, RIQI, XIAOZU) values ('1', 100, '已完成', '2012-02-10', '小组1');
insert into test (ID, MONEY, STATE, RIQI, XIAOZU) values ('2', 300, '未完成', '2012-03-1', '小组1');
insert into test (ID, MONEY, STATE, RIQI, XIAOZU) values ('3', 150, '已完成', '2012-02-15', '小组1');
insert into test (ID, MONEY, STATE, RIQI, XIAOZU) values ('4', 80, '已完成', '2012-02-23', '小组2');
insert into test (ID, MONEY, STATE, RIQI, XIAOZU) values ('5', 30, '已完成', '2012-03-23', '小组2');
select XIAOZU,
substr(RIQI,1,7) month ,
count(decode(STATE,'已完成',1,'')) count1,
sum(decode(STATE,'已完成',money,0)) money1,
count(decode(STATE,'未完成',1,'')) count2,
sum(decode(STATE,'未完成',money,0)) money2
from test
group by XIAOZU,substr(RIQI,1,7)
order by XIAOZU,substr(RIQI,1,7)
xiaozu month count1 money1 count2 money2
----------------------------------------------------
1 小组1 2012-02 2 250 0 0
2 小组1 2012-03 0 0 1 300
3 小组2 2012-02 1 80 0 0
4 小组2 2012-03 1 30 0 0