spring mvc +ExtJs FromPanel提交以后怎样跳转
我想通过spring mvc的方式来控制页面的跳转前台用extjs.
我的后台代码:
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
import org.springframework.stereotype.Controller;
import org.springframework.ui.ModelMap;
import org.springframework.web.bind.ServletRequestUtils;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
@Controller
public class TestController {
     @RequestMapping(value = "/test.htm", method = RequestMethod.POST)
     public String test(HttpSession sesstion, HttpServletRequest request,
             HttpServletResponse response, ModelMap map) {
         //System.out.println("success");
         try {
             String username = ServletRequestUtils.getStringParameter(request,
                     "username");
             //System.out.println(username);
             map.addAttribute("username", username);
         } catch (Exception e) {
             e.printStackTrace();
         }
         return "portfolio/test";//这个是我要跳转的页面
     }
}
前台Extjs代码:
Ext.onReady(function() {
	Ext.loginForm = Ext.extend(Ext.form.FormPanel, {
				xtype : "form",
				title : "登錄",
				labelWidth : 100,
				labelAlign : "center",
				buttonAlign : 'right',
				layout : "form",
				width : 400,
				padding : "10px",
				initComponent : function() {
					this.items = [{
								xtype : "textfield",
								fieldLabel : "使用者名稱",
								name : "username",
								anchor : "95%"
							}, {
								xtype : "textfield",
								fieldLabel : "密碼",
								name : "password",
								anchor : "95%",
								inputType : "password"
							}, {
								xtype : "checkbox",
								boxLabel : "記住登錄狀態",
								name : "spring_security_remember_me",
								anchor : "100%"
							}]
					this.buttons = [{
						xtype : "button",
						text : "登入",
						type : "submit",
						scope : this,
						handler : function() {
							this.getForm().doAction("submit", {
								url : "/test.htm",//我要提交的处理的页面
								scope : this,
								success : function(form, action) {
									alert("success");
								},
								failure : function(form, action) {
									Ext.Msg
											.alert(
													'Warning!',
													'Authentication server is unreachable : '
															+ action.response.responseText);
								}
							})
						}
					}]
					Ext.loginForm.superclass.initComponent.call(this);
				}
			})
	var loginForm = new Ext.loginForm({
				frame : true,
				autoHeight : true,
				renderTo : "login"
			});
})
在Controler中我要返回什么且在Extjs的success模块怎么接收才能实现页面的跳转呢?
------解决方案--------------------
spring里不需要指定跳转页面 那个是同步操作的时候才指定的
直接在后台将test方法改为void 函数中最后response写字符串结果就行