日期:2014-05-16 浏览次数:20774 次
<form action="" method="post" id="frmUserOperation" name="frmUserOperation">
<div id="process"></div>
<input type="hidden" id="method" name="method" value="1111" />
</form>
<script language="javascript" type="text/javascript">
$("#frmUserOperation").submit(function () {
jQuery.ajax({
url: "/Manage/UserOperation",
type: "POST",
beforeSend: function () {
$("#process").html("正在处理...");
},
success: function (data) {
$("#process").html(data);
}
});
return false;
});
</script>
$("#frmUserOperation").submit();
$("#frmUserOperation").submit(function () {
jQuery.ajax({
url: "/Manage/UserOperation",
type: "POST",
data:$(this).serialize(),////////////
beforeSend: function () {
$("#process").html("正在处理...");
},
success: function (data) {
$("#process").html(data);
}
});
return false;
});
------解决方案--------------------
ajax里面 data属性没设置,没有值的传递 楼上正解