日期:2014-05-16 浏览次数:20773 次
<form action="" method="post" id="frmUserOperation" name="frmUserOperation">
        <div id="process"></div>
        <input type="hidden" id="method" name="method" value="1111" />
</form>
<script language="javascript" type="text/javascript">
    $("#frmUserOperation").submit(function () {
        jQuery.ajax({
            url: "/Manage/UserOperation",
            type: "POST",
            beforeSend: function () {
                $("#process").html("正在处理...");
            },
            success: function (data) {
                $("#process").html(data);
            }
        });
        return false;
    });
</script>
        $("#frmUserOperation").submit();
$("#frmUserOperation").submit(function () {
        jQuery.ajax({
            url: "/Manage/UserOperation",
            type: "POST",
            data:$(this).serialize(),////////////
            beforeSend: function () {
                $("#process").html("正在处理...");
            },
            success: function (data) {
                $("#process").html(data);
            }
        });
        return false;
    });
------解决方案--------------------
ajax里面 data属性没设置,没有值的传递    楼上正解