日期:2014-05-16 浏览次数:20689 次
<?xml version="1.0" encoding="utf-8"?>
<string xmlns="http://tempuri.org/">{
"ArrayOfFunction":{
"Actives":"",
"Description":"111",
"FunctionName":"12345",
"PageName":"#",
"PagePath":"#",
"functionid":"05BA37E0-0BA6-4236-9A30-5D4C51D21368"
}
}</string>
var xml = '<?xml version="1.0" encoding="utf-8"?>'+
'<string xmlns="http://tempuri.org/">{'+
' "ArrayOfFunction":{'+
' "Actives":"",'+
' "Description":"111",'+
' "FunctionName":"12345",'+
' "PageName":"#",'+
' "PagePath":"#",'+
' "functionid":"05BA37E0-0BA6-4236-9A30-5D4C51D21368"'+
' }'+
'}</string>';
var json = eval('('+/{[\s\S]+}/.exec(xml)[0]+')');
alert(json)
------解决方案--------------------
最好是解析xml获取需要的节点内容,要不正则提取复制结构的json有得你弄的了
2#就是用正则提取json字符串出来然后eval生成json对象