日期:2013-02-21  浏览次数:21120 次

这是我看完几个base64编码、解码函数后自己改写的。
因为,在中文操作系统的VBscript中,使用的是unicode字符集,所以
很多base64编码、解码函数在理论上是正确的,但实际不能运行!

我加写了几个Unicode与Ansi编码转换的函数,现贴出来,请大家执教!


文件名称base64test.asp

<%

sBASE_64_CHARACTERS = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"  
sBASE_64_CHARACTERS = strUnicode2Ansi(sBASE_64_CHARACTERS)

Function strUnicodeLen(asContents)
  '计算unicode字符串的Ansi编码的长度
  asContents1="a"&asContents
  len1=len(asContents1)
  k=0
  for i=1 to len1
      asc1=asc(mid(asContents1,i,1))
      if asc1<0 then asc1=65536+asc1
      if asc1>255 then
         k=k+2
      else
         k=k+1
      end if
  next
  strUnicodeLen=k-1
End Function

Function strUnicode2Ansi(asContents)
  '将Unicode编码的字符串,转换成Ansi编码的字符串
  strUnicode2Ansi=""
  len1=len(asContents)
  for i=1 to len1
      varchar=mid(asContents,i,1)
      varasc=asc(varchar)
      if varasc<0 then varasc=varasc+65536
      if varasc>255 then
         varHex=Hex(varasc)
         varlow=left(varHex,2)
         varhigh=right(varHex,2)
         strUnicode2Ansi=strUnicode2Ansi & chrb("&H" & varlow ) & chrb("&H" & varhigh )
      else
         strUnicode2Ansi=strUnicode2Ansi & chrb(varasc)
      end if
   next
End function

Function strAnsi2Unicode(asContents)
  '将Ansi编码的字符串,转换成Unicode编码的字符串
  strAnsi2Unicode = ""
  len1=lenb(asContents)
  if len1=0 then exit function
  for i=1 to len1
      varchar=midb(asContents,i,1)
      varasc=ascb(varchar)
      if varasc > 127  then
         strAnsi2Unicode = strAnsi2Unicode & chr(ascw(midb(asContents,i+1,1) & varchar))
         i=i+1
      else
         strAnsi2Unicode = strAnsi2Unicode & chr(varasc)
      end if
  next
End function

Function Base64encode(asContents)  
'将Ansi编码的字符串进行Base64编码
'asContents应当是ANSI编码的字符串(二进制的字符串也可以)
Dim lnPosition  
Dim lsResult  
Dim Char1  
Dim Char2  
Dim Char3  
Dim Char4  
Dim Byte1  
Dim Byte2  
Dim Byte3  
Dim SaveBits1  
Dim SaveBits2  
Dim lsGroupBinary  
Dim lsGroup64  
Dim m4,len1,len2

len1=Lenb(asContents)
if len1<1 then
   Base64encode=""
   exit Function
end if

m3=Len1 Mod 3
If M3 > 0 Then asContents = asContents & String(3-M3, chrb(0))  
'补足位数是为了便于计算

IF m3 > 0 THEN
   len1=len1+(3-m3)
 &nbs