日期:2014-05-17 浏览次数:21001 次
    key1 = request("key1")
    key2 = request("key2")
    key3 = request("key3")
    key4 = request("key4")
    
    sql = "select * from table where 1 = 1"
    if key1 <> "" then
        sql = sql & " and key1 = '"&key1&"'"
    end if
    'key2雷同。。。
    sql = sql & " order by id desc"
------解决方案--------------------
更新列表是什么意思?
------解决方案--------------------
更新列表
rs.open sqlstr,conn,1,1
 response.write("<table  ><tr>")
for each x in rs.fields
   response.write("<td>"&x.name&"</td>")   
next
 response.write("</tr>")
 do until rs.eof
 response.write("<tr>")
 for each x in rs.fields
  response.write("<td>"&x.value&"</td>")  
  next
   response.write("</tr>")
   
rs.movenext
loop
 response.write("</table>")
------解决方案--------------------
  key1 = request("key1")
    key2 = request("key2")
    key3 = request("key3")
    key4 = request("key4")
    
    sql = "select * from table where 1 = 1"
    sql2 = "update table set "
    if key1 <> "" then
        sql = sql & " and key1 = '"&key1&"'"
        sql2 = sql2 & " key1 = '"&key1&"',"
    end if
    'key2雷同。。。
    sql = sql & " order by id desc"