日期:2014-05-17 浏览次数:20997 次
key1 = request("key1")
key2 = request("key2")
key3 = request("key3")
key4 = request("key4")
sql = "select * from table where 1 = 1"
if key1 <> "" then
sql = sql & " and key1 = '"&key1&"'"
end if
'key2雷同。。。
sql = sql & " order by id desc"
------解决方案--------------------
更新列表是什么意思?
------解决方案--------------------
更新列表
rs.open sqlstr,conn,1,1
response.write("<table ><tr>")
for each x in rs.fields
response.write("<td>"&x.name&"</td>")
next
response.write("</tr>")
do until rs.eof
response.write("<tr>")
for each x in rs.fields
response.write("<td>"&x.value&"</td>")
next
response.write("</tr>")
rs.movenext
loop
response.write("</table>")
------解决方案--------------------
key1 = request("key1")
key2 = request("key2")
key3 = request("key3")
key4 = request("key4")
sql = "select * from table where 1 = 1"
sql2 = "update table set "
if key1 <> "" then
sql = sql & " and key1 = '"&key1&"'"
sql2 = sql2 & " key1 = '"&key1&"',"
end if
'key2雷同。。。
sql = sql & " order by id desc"