asp 分 类型 登陆的问题,求解决方法!!!!!
我的目的   登陆的时候可以分2种类型   选择一种之后   到数据库会搜索相应的类型字段   进行判断.      
 数据库字段   1.username(此为邮件地址)2.nickname(昵称)3.pass(密码)   4.power(权限)      
 提交数据页面的   下拉框:    
  <select   ID= "Select1 "   NAME= "type ">  <option   name= "Email "> 邮件地址 </option>  <option   name= "Nick "> 昵称 </option>  </select>       
 登陆判断页面.    
 loginfinsh.asp      
 strType=trim(request.Form( "Type "))    
 strUse=trim(request.Form( "UserName "))    
 strPass=trim(request.Form( "pass "))      
 const   strConn   =    "driver={SQL   Server};server=172.16.0.3;uid=sysdba;pwd=masterkey;database=kingcrm "    
 set   Conn   =   server.CreateObject   ( "ADODB.Connection ")    
 Conn.Open   strConn      
 set   rs=server.CreateObject( "ADODB.Recordset ")      
 if   strType= "邮件地址 "   then      
 strSQL   =    "select   *   from   sysdba.UserTablebackup1   where   UserName= ' "   &   strUse   &    " '   and   pass= ' "   &   strPass   &    " ' "    
 rs.Open   strSQL,Conn,1,1    
 if   rs.EOF   or   rs.BOF   then    
 Response.Write    " <font   face= '华文新魏 '   size= '5 '> 登陆失败,请确定用户名和密码!! </font>  <br>  "    
 Response.Write    " <a   href= 'index.asp '> 返回 </a>  "    
 else    
 Session( "UserName ")=rs( "UserName ")    
 Session( "pass ")=rs( "Pass ")    
 Session( "power ")=rs( "power ")    
 Response.Redirect( "SY_index.html ")    
 end   if      
 elseif   strType= "昵称 "   then      
 strSQL   =    "select   *   from   sysdba.UserTablebackup1   where   NickName= ' "   &   strUse   &    " '   and   pass= ' "   &   strPass   &    " ' "    
 rs.Open   strSQL,Conn,1,1    
 if   rs.EOF   or   rs.BOF   then    
 Response.Write    " <font   face= '华文新魏 '   size= '5 '> 登陆失败,请确定用户名和密码!! </font>  <br>  "    
 Response.Write    " <a   href= 'index.asp '> 返回 </a>  "    
 else    
 Session( "UserName ")=rs( "UserName ")    
 Session( "pass ")=rs( "Pass ")    
 Session( "power ")=rs( "power ")    
 Response.Redirect( "SY_index.html ")    
 end   if    
 end   if    
 rs.Close    
 conn.Close    
 set   rs=nothing    
 set   Conn=nothing    
------解决方案--------------------if strType= "邮件地址 " then  
   strSQL =  "UserName= ' " & strUse &  " ' " 
 else 
   strSQL =  "NickName= ' " & strUse &  " ' " 
 end if   
 sql =  "select .... where  " & strSQL &  " and pass= ' " & strPass &  " ' "   
 set rs