刚刚学习winform，调试时总提示密码错误，我连接的是 access数据库，密码是111，请指教！
数据库连接字符串如下：总是在"conn.Open();"出错，提示密码不正确！可是就是111呀？我也打开数据库，手工输入密码“111”能够正常打开！

            string DiZhi = System.Environment.CurrentDirectory;

            string str_conn = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + DiZhi + "\\system.mdb;Persist Security Info=True;Jet OLEDB:Database Password=111";

------解决方案--------------------

 public class sqlhelper

    {

        



        public sqlhelper()

        {

            //

            //TODO: 在此处添加构造函数逻辑

            //

        }



        public static string connstr = ConfigurationManager.AppSettings["accessConnStr"].ToString() + HttpContext.Current.Server.MapPath(ConfigurationManager.AppSettings["accessdbPath"].ToString()) + ";";



        public static string cupage()

        {

            string strPath = "http://" + HttpContext.Current.Request.ServerVariables["HTTP_HOST"] + HttpContext.Current.Request.ServerVariables["PATH_INFO"] + "?" + HttpContext.Current.Request.ServerVariables["QUERY_STRING"];

            if (strPath.EndsWith("?"))

            {

                strPath = strPath.Substring(0, strPath.Length - 1);

            }

            return strPath;

        }





        public static int ExecuteNonQuery(CommandType cmdType, string cmdText, params OleDbParameter[] commandParameters)

        {

            OleDbCommand cmd = new OleDbCommand();