日期:2014-05-18 浏览次数:21038 次
using (System.Windows.Forms.OpenFileDialog flg = new OpenFileDialog())
{
if (flg.ShowDialog() == DialogResult.OK)
{
string strFileName = System.IO.Path.GetFileName(flg.FileName);
string strFileDir = System.IO.Path.GetDirectoryName(flg.FileName);
}
}