请教Hashtable排序问题!
我用C#写了一个福彩双色球程序,关键代码如下: 
 public   void   CreatRandomNum() 
 		{ 
 			Hashtable   hashtable   =   new   Hashtable(); 
 			Random   random   =   new   Random(); 
 			int   numCount   =   6; 
 			for   (int   i   =   0;hashtable.Count <numCount;i++) 
 			{ 
 				int   nValue=random.Next(34); 
 				if(!hashtable.ContainsValue(nValue)&&nValue!=0) 
 				{ 
 					hashtable.Add(nValue,nValue); 
 					this.txtRedBall.Text+=nValue.ToString()+ "          "; 
 				} 
 			} 
 			this.txtBlueBall.Text=random.Next(16)+1+ " "; 
 		}   
 		private   void   btnOpen_Click(object   sender,   System.EventArgs   e) 
 		{ 
 			this.txtRedBall.Text= " "; 
 			this.txtBlueBall.Text= " "; 
 			CreatRandomNum(); 
 		}   
 		private   void   btnClear_Click(object   sender,   System.EventArgs   e) 
 		{ 
 			this.txtRedBall.Text= " "; 
 			this.txtBlueBall.Text= " "; 
 		}   
 		private   void   btnExit_Click(object   sender,   System.EventArgs   e) 
 		{ 
 			Application.Exit(); 
 		} 
 现在想对显示在txtRedBall中的数字从小到大排序,不会搞了,请各位帮一下忙,谢谢!
------解决方案--------------------List <Int16>  list = new List <short> (); 
         Random random = new Random(); 
         int numCount = 6; 
         for (int i = 0; list.Count  < numCount; i++) 
         { 
             int nValue = random.Next(34); 
             if (!list.Contains(nValue)&& nValue != 0) 
             { 
                 list.Add(nValue); 
             } 
         } 
         list.Sort(); 
         string text = string.Empty; 
         foreach (Int16 x in list) 
         { 
             text += x.ToString(); 
         } 
 this.txtRedBall.Text = text;