DataGird分页问题
加入了下面这段代码
        private   void   dataGrid1_PageIndexChanged(object   source,   System.Web.UI.WebControls.DataGridPageChangedEventArgs   e)
        {
                dataGrid1.CurrentPageIndex   =   e.NewPageIndex;
                dataGrid1.DataBind();
        }  

浏览时还是只显示分页，点击无效果，不知道是怎么回事？

------解决方案--------------------
如果在Page_Load里绑定了，最好判断回传
if(!IsPostBack)
{

}
------解决方案--------------------
private void Page_Load(object sender, System.EventArgs e)
{
if (! IsPostBack )
{
//这里加上你的绑定方法
}

}

private void dataGrid1_PageIndexChanged(object source, System.Web.UI.WebControls.DataGridPageChangedEventArgs e)
{
dataGrid1.CurrentPageIndex = e.NewPageIndex;
//这里加上你的绑定方法
}
------解决方案--------------------
SqlConnection conn = new SqlConnection(ConfigurationSettings.AppSettings[ "sqlConnection "]);
conn.Open();
string readmsgSql = "SQL语句 ";
SqlDataAdapter readmsgdap = new SqlDataAdapter(readmsgSql,conn);
DataSet Msgs = new DataSet();
readmsgdap.Fill(Msgs, "Messages ");


this.dataGrid1.DataSource = Msgs.Tables[0];
this.dataGrid1.DataBind();
把这些代码中写到一个方法中，绑定的时候才调用
------解决方案--------------------
1，首先也第一次刷新时要绑定。
2，dataGrid1 的PageIndexChanged 要指向 void dataGrid1_PageIndexChanged
3,dataGrid1.CurrentPageIndex变为新页后要重新绑定

以下为简单的代码

protected void Page_Load(object sender, EventArgs e)
{
if(!Page.IsPostBack)
{
this.Bind
}
}
private void dataGrid1_PageIndexChanged(object source, System.Web.UI.WebControls.DataGridPageChangedEventArgs e)
{
dataGrid1.CurrentPageIndex = e.NewPageIndex;
this.Bind()
}

private void Bind() {

SqlConnection conn = new SqlConnection(ConfigurationSettings.AppSettings[ "sqlConnection "]);
conn.Open();
string readmsgSql = "SQL语句 ";
SqlDataAdapter readmsgdap = new SqlDataAdapter(readmsgSql, conn);
DataSet Msgs = new DataSet();
readmsgdap.Fill(Msgs, "Messages ");

this.dataGrid1.DataSource = Msgs.Tables[0];
this.dataGrid1.DataBind();

}