如何将XML文件转化为字符串,如何将字符串转化为XML文件
如题,谢谢!
------解决方案--------------------将文件读出来就成了字符串,将字符串保存起来就成了文件 活活
------解决方案--------------------//XML String 
    string strXML = @ " <?xml version= '1.0 ' encoding= 'UTF-8 '?>  " + 
      " <SCSShippingInfo>  " + 
      " <IsSuccess> Y </IsSuccess>  " + 
      " <Message> Success! </Message>  " + 
      " <ErpData>  " + 
       " <INVOICE_NO> l9128565 </INVOICE_NO>  " + 
       " <SCS_QTY> 96 </SCS_QTY>  " + 
       " <ORG> M01 </ORG>  " + 
       " <STATUS> NULL </STATUS>  " + 
       " <OQC_CHECK_TIME> NULL </OQC_CHECK_TIME>  " + 
       " <SHIPPING_TIME> 2007-03-07 18:10:38.0 </SHIPPING_TIME>  " + 
      " </ErpData>  " + 
      " </SCSShippingInfo>  ";    
    //Load Xml 
    XmlDocument xmlDoc = new XmlDocument(); 
    xmlDoc.LoadXml(strXML);
------解决方案--------------------XmlDocument xmlDoc = new XmlDocument(); 
             try 
             { 
                 xmlDoc.LoadXml(content);//content是XML字符串 
             } 
             catch (Exception e) 
             { 
                 throw new AppException( "不是XML文档格式或是XML语法错误 ", e); 
             } 
             XmlNode rootNode = xmlDoc.DocumentElement; 
             if (rootNode.Name.ToLower() !=  "documentinfo ") 
             { 
                 return SQLAccessState.Fault; //不是公文信息 
             } 
             try 
             { 
                 XmlNode archiveInfoNode = rootNode.SelectSingleNode( "DocInfo ");//用XPath表达示取得节点值 
                 string date = archiveInfoNode.SelectSingleNode( "PublicDate ").InnerText.ToString(); 
                 if (date ==  " " || date == null) 
                 { 
                     date = System.DateTime.Today.ToString(); 
                 } 
                 archiveInfo.DocNo = archiveInfoNode.SelectSingleNode( "DocNo ").InnerText.ToString(); 
                 archiveInfo.Title = archiveInfoNode.SelectSingleNode( "Title ").InnerText.ToString(); 
                 archiveInfo.SendUnitCode = archiveInfoNode.SelectSingleNode( "SendUnitCode ").InnerText.ToString(); 
                 archiveInfo.PublicDate = Convert.ToDateTime(date); 
                 archiveInfo.Urgent = archiveInfoNode.SelectSingleNode( "Urgent ").InnerText.ToString(); 
                 archiveInfo.Secret = archiveInfoNode.SelectSingleNode( "Secret ").InnerText.ToString(); 
                 archiveInfo.Subject = archiveInfoNode.SelectSingleNode( "Subject ").InnerText.ToString(); 
                 archiveInfo.KeyWord = archiveInfoNode.SelectSingleNode( "KeyWord ").InnerText.ToString(); 
                 archiveInfo.Drafter = archiveInfoNode.SelectSingleNode( "Drafter ").InnerText.ToString(); 
                 archiveInfo.Dutyman = archiveInfoNode.SelectSingleNode( "Dutyman ").InnerText.ToString(); 
                 archiveInfo.Remark = archiveInfoNode.SelectSingleNode( "Remark ").InnerText.ToString(); 
                 archiveInfo.IsDeleted = Convert.ToInt32(archiveInfoNode.SelectSingleNode( "Status ").InnerText.ToString()); 
             } 
             catch(Exception e) 
             { 
                 throw new AppException( "XML文档中公文信息节点不正确 ", e); 
             }
------解决方案--------------------