日期:2014-05-20 浏览次数:21475 次
String str="aaaaxxxxxxxxbbbb";
String begin="aaaa";
String end="bbbb";
Matcher m=Pattern.compile("^"+begin+"(.*)"+end+"$").matcher(str);
if(m.find())
System.out.println(m.group(1));
------解决方案--------------------
public class Test {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
String s="nimabi";
String pre="ni";
String suf="bi";
System.out.println(s.substring((s.indexOf(pre)+pre.length()), s.indexOf(suf)));
}
}
------解决方案--------------------
static String getStr(String src,String beg,String end){
String regex = beg+"(.*)"+end;
System.out.println(regex);
Pattern p = Pattern.compile(regex);
Matcher m = p.matcher(src);
if(m.find()){
return m.group(1);
}
return null;
}
public static void main(String[] args)
{
System.out.println(getStr("aaa12121212dde", "aaa", "dde"));
}
------解决方案--------------------
public static void main(String[] args) {
String s = "楼主你给我100分!";
String mid = s.replaceAll(".*你(.*)!.*", "$1");
System.out.println(mid);
}
------解决方案--------------------
package com.xuyisen.socket.socket;
public class Test {
/**
* 截取字符串source中begin到end之间的字符串
* @param source 源字符串
* @param begin 开始
* @param end 结束
* @return
*/
public String subString(String source,String begin, String end){
String result = "";
if(!source.contains(begin)){
result = "源字符串中没有字符串: " + begin;
return result;
}else if(!source.contains(end)){
result = "源字符串中没有字符串: " + end;
return result;
}
int beginIndex = source.indexOf(begin);
int endIndex = source.indexOf(end);
result = source.substring(beginIndex+begin.length(), endIndex);
return result;
}
public static void main(String[] args) {
Test t = new Test();
String str = "louzhugeiwojiafen,ok";
String begin = "louzhu";
String end = ",ok";
String s = t.subString(str, begin, end);
System.out.println(s);
}
}