public class Test981 {

    public static void reflect(String... str){
        Pattern p1 = Pattern.compile("\\[\\d+:\\d+\\]");
        Pattern p2 = Pattern.compile("JF?K?\\d+");
        for (String string : str) {
            Matcher m1 = p1.matcher(string);
            Matcher m2 = p2.matcher(string);
            if(m1.find())
                System.out.println(m1.group().replaceAll("[\\[\\]]", ""));
            if(m2.find())
                System.out.println(m2.group());
        }
    }
    
    public static void main(String[] args) {

        String s1 = "[21231853:680492]smpp_TAQ:_13189867588_1_aaaaaaaa_J2012052123360846583";
        String s2 = "[21231853:861244]smpp_TUQ:_JFK20120521510548945_13249852861_1_aaaaaaaa_3000_0_N_2012-05-21 23:36:08_511201167443476";

        reflect(s1 , s2);
    }

}

------解决方案--------------------

Java code

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Wei5445 {

    /**
     * @param args
     */
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        regexStr();
    }
    
    public static void regexStr(){
        String str1 = "[21231853:680492]smpp_TAQ:_13189867588_1_aaaaaaaa_J2012052123360846583",
               str2 = "[21231853:861244]smpp_TUQ:_JFK20120521510548945_13249852861_1_aaaaaaaa_3000_0_N_2012-05-21 23:36:08_511201167443476";
        
        String regex = "\\[(\\d+:\\d+)\\]smpp_T[AU]{1}Q:.*?_([a-zA-Z]+\\d+).*?";
        
        Matcher m = Pattern.compile(regex).matcher(str1);
        
        while(m.find()){
            System.out.println(m.group(1));
            System.out.println(m.group(2));
        }
        
    }

}
运行：
21231853:680492
J2012052123360846583

------解决方案--------------------

Java code

    public static void main(String[] args) {
        String s = "I.[21231853:680492]smpp_TAQ:_13189867588_1_aaaaaaaa_J2012052123360846583";
//        String s = "I.[21231853:861244]smpp_TUQ:_JFK20120521510548945_13249852861_1_aaaaaaaa_3000_0_N_2012-05-21 23:36:08_511201167443476";
        Matcher m = Pattern.compile("\\[(.+?)\\].+?_(J[^_]+)(_.+)?").matcher(s);
        while(m.find()){
            System.out.println(m.group(1));
            System.out.println(m.group(2));
        }
    }

------解决方案--------------------

for example
Java code
String[] arr = {"I.[21231853:680492]smpp_TAQ:_13189867588_1_aaaaaaaa_J2012052123360846583",
                "I.[21231853:861244]smpp_TUQ:_JFK20120521510548945_13249852861_1_aaaaaaaa_3000_0_N_2012-05-21 23:36:08_511201167443476"};
for (String s : arr) {
    //替换后分割，sa[0]，sa[1]就是LZ所需要的
    String[] sa = s.replaceAll(".*?\\[(\\d+:\\d+)\\].*?(J[A-Z]*\\d+).*", "$1,$2").split(",");
    System.out.printf("first=%s, second=%s\n", sa[0], sa[1]);
}