出现1次的号码5注:
533 574 575 735 773   

出现2次的号码6注:
333 373 554 573 733 755   

出现3次的号码3注:
473 484 775

------解决方案--------------------

Java code

import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class NumberSort {
    static String s;
    // 模拟文件读取
    static {
        s = "出现1次的号码5注:\r\n";
        s += "533 574 575 735 773\r\n";
        s += "\r\n";
        s += "出现2次的号码6注:\r\n";
        s += "333 373 554 573 733 755\r\n";
        s += "\r\n";
        s += "出现3次的号码3注:\r\n";
        s += "473 484 775\r\n";
    }

    public static void main(String[] args) {
        List<Integer> list = new ArrayList<Integer>();
        // 通过正则找出三位数的数组放进list中
        Matcher m = Pattern.compile("\\d{3}").matcher(s);
        while (m.find()) {
            list.add(new Integer(m.group()));
        }
        // 给list排序
        Collections.sort(list);

        StringBuilder sb = new StringBuilder();
        System.out.println("出现1次的号码" + list.size() + "注:");
        for (int i = 0; i < list.size(); i++) {
            sb.append(list.get(i)).append(" ");

            if ((i + 1) % 10 == 0) {
                sb.append("\r\n");
            }
        }
        // 结果
        String result = sb.toString().trim();
        System.out.println(result);
    }

}

------解决方案--------------------

Java code

public static void main(String[] args) throws IOException {
        File file = new File("file.txt");
        BufferedReader br = new BufferedReader(new FileReader(file));
        List<Integer> numbers = new ArrayList();
        StringBuffer str = new StringBuffer();
        String temp ;
        while((temp = br.readLine()) != null){
            str.append(temp);
        }
        br.close();
        Pattern pattern = Pattern.compile("\\d{3}");
        Matcher matcher = pattern.matcher(str.toString());
        while(matcher.find()){
            numbers.add(Integer.parseInt(matcher.group()));
        }
        Collections.sort(numbers);
        for (int i = 0; i < numbers.size(); i++) {
            System.out.print(numbers.get(i) + "\t");
            if( i != 0 && i % 10 == 0)System.out.println();
        }
    }

------解决方案--------------------

Java code

    public static void main(String[] args) throws IOException {
        File file = new File("file.txt");
        BufferedReader br = new BufferedReader(new FileReader(file));
        List<Integer> numbers = new ArrayList();
        StringBuffer str = new StringBuffer();
        String temp ;
        while((temp = br.readLine()) != null){
            str.append(temp);
        }
        br.close();
        Pattern pattern = Pattern.compile("\\d{3}");
        Matcher matcher = pattern.matcher(str.toString());
        while(matcher.find()){
            numbers.add(Integer.parseInt(matcher.group()));
        }
        Collections.sort(numbers);
        System.out.println("出现一次的号码为：" + numbers.size() + "注");
        for (int i = 0; i < numbers.size(); i++) {
            System.out.print(numbers.get(i) + "\t");
            if((i + 1) % 10 == 0)System.out.println();
        }        
    }