gauge怎么滚动的不对呀？
小弟照着书写了一个进度条的例程，就是10格子的进度条，每秒走一格。可是不知道为什么每次走到5格就停止了。我输出了走格子的变量，它是一直走到10的，不知道怎么回事。哪位好心人指点一下。

import   javax.microedition.midlet.*;
import   javax.microedition.lcdui.*;
public   class   AlertDemo   extends   MIDlet   implements   CommandListener{
private   final   static   Command   CMD_EXIT   =new   Command( "Exit ",Command.EXIT   ,1);
private   Alert   alert;
private   Form   form;
private   final   int   timeout=10000;

public   AlertDemo()
{
    alert   =   new   Alert( "AlertDemo ", "Information   Alert   Rujnig ",null,AlertType.INFO   );
   
    form   =   new   Form( "Next   Screen ");
   
}

protected   void   destroyApp(boolean   arg0)   throws   MIDletStateChangeException   {
    //   TODO   Auto-generated   method   stub
   
}

protected   void   pauseApp()   {
    //   TODO   Auto-generated   method   stub
   
}

protected   void   startApp()   {
    //   TODO   Auto-generated   method   stub
    Display.getDisplay(this).setCurrent(alert,form);
    alert.setTimeout(timeout);
    Gauge   indicator=createIndicator(timeout);
    alert.setIndicator(indicator);
    form.append( "Alert   has   done! ");
    form.addCommand(CMD_EXIT);
    form.setCommandListener(this);
}

public   void   commandAction(Command   c,   Displayable   d)   {
    //   TODO   Auto-generated   method   stub
    if   (c==CMD_EXIT)
    {
      try   {
        destroyApp(false);
      }   catch   (MIDletStateChangeException   e)   {
        //   TODO   Auto-generated   catch   block
        e.printStackTrace();
      }
      notifyDestroyed();
    }
}

public   Gauge   createIndicator(int   maxValue)
{
    if(maxValue==Alert.FOREVER)
    {
      return   new   Gauge(null,false,Gauge.INDEFINITE,Gauge.CONTINUOUS_RUNNING);
    }
    final   int   max=maxValue/1000;
    System.out.println(max);
    final   Gauge   indicator=new   Gauge(null,false,max,0);
    new   Thread()
    {
      public   void   run()
      {
        int   value=0;
        while(value <max)
        {
          indicator.setValue(value++);
         
          System.out.println(value);
          try
          {
            Thread.sleep(1000);
          }
          catch(Exception   e)