var str ="SKU001,SKU001,SKU003,SKU002,......";

最后显示：
SKU001:2
SKU002:1
SKU003:1


其中str内容是不定的。

  var str = "SKU001,SKU001,SKU003,SKU002,SKU003,SKU003,SKU004,SKU004";
    var arrs = str.split(',');
    var object = {};
    for (var i = 0; i < arrs.length; i++) {
        var str = "if(object['" + arrs[i] + "'])object['" + arrs[i] + "']++; else object['" + arrs[i] + "'] =1; ";
        eval(str);
    }
    for (var p in object) {
        document.write(p + ":" + object[p]+"<br>");
    }

------解决方案--------------------
探讨


是滴，
统计重复的个数。。


------解决方案--------------------
JScript code
    var str = "SKU001,SKU001,SKU003,SKU002";
    var kv = {};
    str.replace(/([^,]+)/gi, function ($1) { if (kv[$1]) kv[$1] += 1; else kv[$1] = 1; })
    for (var k in kv) document.write(k + ':'+kv[k]+'<br/>');

------解决方案--------------------
JScript code

<script type="text/jscript">
var str ="SKU001,SKU001,SKU003,SKU002,......";
var key = str.split(",");
var result = "";
for(var i =0,len=key.length;i<len;i++){
    if(result.indexOf(key[i]) < 0){
        result += key[i]+"出现次数"+(str.split(key[i]).length-1)+"\n";
    }
}
alert(result);
</script>

------解决方案--------------------
探讨


JScript code

<script type="text/jscript">
var str ="SKU001,SKU001,SKU003,SKU002,......";
var key = str.split(",");
var result = "";
for(var i =0,len=key.length;i<len;i++){
    if(result.indexOf(key……