用javascript取url参数值的问题
function   Request(name,url) 
 { 
          new   RegExp( "(^|&) "+name+ "=([^&]*) ").exec(url); 
          return   RegExp.$2 
 }   
 var   str= "http://localhost/abc.aspx?aa=1 "   
 单独只取一次值alert(Request( "aa "))得结果是1 
 如取不存在的alert(Request( "cc "))则为空   
 但是,如果是两个都取的话,就出问题了 
 比如 
 alert( "aa= "+Request( "aa ")); 
 alert( "cc= "+Request( "cc ")); 
 取得aa=1,第二个也是cc=1   
 先取cc,再取aa,就没有问题 
 alert( "cc= "+Request( "cc "));   //返回空 
 alert( "aa= "+Request( "aa "));   //反回aa=1   
 估计是regexp内存没有释放的缘故吧,可是又不知道怎么样能清空前一个regexp,请高手指教
------解决方案--------------------try   
  <script language=javascript>  
 function Request(name,url) 
 { 
 return (new RegExp( "(\\?|&) "+name+ "=([^&]*) ").exec(url))?RegExp.$2: " " 
 }   
 var str= "http://localhost/abc.aspx?aa=1 " 
 alert( "cc= "+Request( "cc ",str)); 
 alert( "aa= "+Request( "aa ",str)); 
 alert( "cc= "+Request( "cc ",str)); 
 	 </script>