关于万年历的实现
我现在想做个万年历,然后在某一天上面显示我想要显示的东西,求大神指导
              
                  JS
              
------解决方案--------------------<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>无标题文档</title>
<style type="text/css">
td[colspan]{
	text-align:center;
	height:auto;
}
table{
	border-collapse:collapse;
	border-style:solid;
}
th{
	width:50px;
	background-color:#0FF;
}
td{
	border-style:solid;
	height:50px;
	vertical-align:top;
}
</style>
<script type="text/javascript">
	function init(){
		var year=document.getElementById("year");
		for(var i=2000;i<=2100;i++){
			var option=document.createElement("option");
			option.value=i;
			option.innerHTML=i+"年";
			year.appendChild(option);
			if(i==2013){
				option.selected=true;
			}
		}
		var month=document.getElementById("month");
		for(var i=1;i<=12;i++){
			var option=document.createElement("option");
			option.value=i;
			if(i<10){
				option.innerHTML='0'+i+"月";
			}else{
				option.innerHTML=i+"月";
			}
			month.appendChild(option);
		}
		var table=document.getElementById("test");
		for(var i=1;i<=6;i++){
			var tr=document.createElement("tr");
			for(var j=1;j<=7;j++){
				var td=document.createElement("td");
				td.setAttribute("num",j);
				tr.appendChild(td);
			}
			table.appendChild(tr);
		}
		year.onchange=showDate;
		month.onchange=showDate;
	}
	function showDate(){
		var md1=[31,28,31,30,31,30,31,31,30,31,30,31];
		var md2=[31,29,31,30,31,30,31,31,30,31,30,31]
		var month=document.getElementById("month").value;
		var year=document.getElementById("year").value;
		var date=new Date(year,month-1,1);
		var tbody=document.getElementById("test");
		var tds=tbody.getElementsByTagName("td");
		for(var i=1;i<tds.length;i++){
			tds[i].innerHTML="";
			tds[i].style.backgroundColor="#CCC";
		}
		var day=date.getDay();
		var now="";
		var leap=isLeap(year);
		if(leap){
			now=md2;
		}else{
			now=md1;
		}
		day=day%7+1;
		for(var i=1;i<day;i++){
			var t=(month-2)>-1?(month-2):11;
			if(month<1){
				var y=year-1;
			}else{
				y=year;
			}
			tds[i].innerHTML=now[t]-(day-i)+1;
			var key=getKey(y,t,tds[i].innerHTML);
			tds[i].innerHTML+="<br/>"+getCookie(key);
			addEvent(tds[i],key);
		}
		for(var i=0;i<now[month-1];i++){
			tds[day].innerHTML=i+1;
			var key=getKey(year,month-1,tds[day].innerHTML);
			tds[day].innerHTML+="<br/>"+getCookie(key);
			tds[day].style.backgroundColor="white";
			var t=tds[day].getAttribute("num");
			if(t==1
------解决方案--------------------t==7){
				tds[day].style.backgroundColor='red';
			}
			addEvent(tds[day],key);
			day++;
		}
		for(var i=day;i<tds.length;i++){
			tds[i].innerHTML=i+1-day;
			var key=getKey(year,month,tds[i].innerHTML);
			tds[i].innerHTML+="<br/>"+getCook