日期:2014-05-17  浏览次数:20534 次

字符串操作
表A
FNAME DETAILSTR
ABC 36.5*5+37.5+37*2+45.2+36
转换成表B
FNAME FNUM
ABC 36.5
ABC 36.5
ABC 36.5
ABC 36.5
ABC 36.5
ABC 37.5
ABC 37
ABC 37
ABC 45.2
ABC 36
------------------------
根据字符串里的数量转换成表B的形式,在sql2000中该怎么处理

------解决方案--------------------
SQL code
if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([FNAME] varchar(3),[DETAILSTR] varchar(24))
insert [tb]
select 'ABC','36.5*5+37.5+37*2+45.2+36'
go

SELECT A.FNAME,A.FNUM
FROM
  (
    select 
      fname,
      fnum=left(fnum+'*',charindex('*',fnum+'*')-1),
      qty=case when charindex('*',fnum)>0 then right(fnum,len(fnum)-charindex('*',fnum)) else 1 end
    from
      (
        select 
          a.FNAME,
          FNUM=substring(a.DETAILSTR,b.number,charindex('+',a.DETAILSTR+'+',b.number)-b.number)
        from tb a,master..spt_values b
        where b.type='P' and charindex('+','+'+a.DETAILSTR,b.number)=b.number
      ) t
  ) A
JOIN MASTER..SPT_VALUES B ON B.TYPE='P' AND A.QTY>B.NUMBER

/**
FNAME FNUM
----- -------------------------
ABC   36.5
ABC   36.5
ABC   36.5
ABC   36.5
ABC   36.5
ABC   37.5
ABC   37
ABC   37
ABC   45.2
ABC   36

(10 行受影响)
**/

------解决方案--------------------
早上在看叶子的博客,改了下
SQL code
create function [dbo].[m_split](@c varchar(2000),@split1 varchar(2),@split2 varchar(2),@name varchar(5))  
    returns @t table(fname varchar(5),col varchar(200))  
as  
begin  
      declare @i int
      while (charindex(@split1,@c)<>0 )
        begin  
          if(charindex(@split2,@c)<>0 and charindex(@split2,@c)<charindex(@split1,@c))
          begin
           set @i=cast(replace(left(@c,charindex(@split1,@c)-1),left(@c,charindex(@split2,@c)),'') as int)
           while(@i>0)
           begin
            insert @t(fname,col) values (@name,substring(@c,1,charindex(@split2,@c)-1))
            set @i=@i-1  
           end
           set @c = stuff(@c,1,charindex(@split1,@c),'')  
          end 
          else
          begin
             insert @t(fname,col) values (@name,substring(@c,1,charindex(@split1,@c)-1))  
             set @c = stuff(@c,1,charindex(@split1,@c),'')  
          end 
        end
      if(charindex(@split2,@c)<>0)
      begin
         set @i=cast(replace(@c,left(@c,charindex(@split2,@c)),'') as int)
         while(@i>0)
         begin
           insert @t(fname,col) values (@name,substring(@c,1,charindex(@split2,@c)-1))
           set @i=@i-1  
         end 
      end   
      else
       insert  @t(fname,col) values (@name,@c)  
      return  
end

if object_id('[tb]') is not null drop table [tb]
go
create table [tb]([FNAME] varchar(3),[DETAILSTR] varchar(24))
insert [tb]
select 'ABC','36.5*5+37.5+37*2+45.2+36'
go
declare @sql varchar(40),@name varchar(5)
select @sql=DETAILSTR,@name=FNAME  from tb
select * from dbo.m_split(@sql,'+','*',@name)

fname    col
ABC    36.5
ABC    36.5
ABC    36.5
ABC    36.5
ABC    36.5
ABC    37.5
ABC    37
ABC    37
ABC    45.2
ABC    36