if object_id('[tb]') is not null drop table [tb]
create table [tb] (id int,name varchar(1),pid int)
insert into [tb]
select 1,'A',0 union all
select 2,'B',1 union all
select 3,'D',1 union all
select 4,'C',2 union all
select 5,'D',2 union all
select 6,'A',4 union all
select 7,'E',5 union all
select 8,'F',5
GO
;with cte
as
(
    select   *,[path]=cast([name]+'->' as varchar(100)) ,[level] = 1 from tb where pid = 0
    union all
    select a.*,  cast(c.[path]+a.[name]+'->' as varchar(100)),[level]+1 from cte c ,tb a where a.pid = c.id
)
select 
* 
from cte
where len([path]) > 6 and right([path],3) = left([path],3)
/*
id          name pid         path           level
----------- ---- ----------- -------------- -----
6           A    4           A->B->C->A->     4

(1 行受影响)
*/

------------------------------------
-- Author : happyflystone  
-- Date   : 2010-04-06 
-- Version: Microsoft SQL Server 2005 - 9.00.2047.00 (Intel X86) 
--          Apr 14 2006 01:12:25 
--          Copyright (c) 1988-2005 Microsoft Corporation
--          Standard Edition on Windows NT 5.2 (Build 3790: Service Pack 2)
--      
------------------------------------

-- Test Data: ta
IF OBJECT_ID('[tb]') IS NOT NULL 
    DROP TABLE [tb]
Go
CREATE TABLE tb([cid] NVARCHAR(1),[pid] NVARCHAR(1))
Go
INSERT INTO tb
    SELECT 'A','B' UNION ALL
    SELECT 'A','D' UNION ALL
    SELECT 'B','C' UNION ALL
    SELECT 'B','D' UNION ALL
    SELECT 'C','A' UNION ALL
    SELECT 'D','E' UNION ALL
    SELECT 'D','F' 
GO
--Start
;with cte
as
(
    select   *,[path]=cast([cid]+'->' as varchar(100)) ,[level] = 1 
    from (select distinct cid,cast('' as nvarchar(1))  as pid from tb union  select distinct pid ,'' from tb) b 
    union all
    select a.*,cast(a.[cid]+'->'+c.[path] as varchar(100)),[level]+1 
    from cte c ,tb a 
    where a.pid = c.cid and charindex(a.[cid]+'->',c.[path])=0
)
select 
[path]+cid+'->'
from cte
where exists(select 2 from tb where cid+'->' = right([path],3) and pid+'->' = left([path],3))-- = left([path],3)


--Result:
/*
--------------
A->B->C->A->
C->A->B->C->
B->C->A->B->

(3 行受影响)

*/
--End 




本文来自CSDN博客，转载请标明出处：http://blog.csdn.net/htl258/archive/2010/04/06/5456223.aspx

BOM循环问题，参考上诉资料

------解决方案--------------------
参考下面的内容,自己修改一下即可.

SQL code

/*
标题：SQL SERVER 2000中查询指定节点及其所有父节点的函数(表格形式显示)
作者：爱新觉罗·毓华(十八年风雨,守得冰山雪莲花开) 
时间：2008-05-12
地点：广东深圳
*/

create table tb(id varchar(3) , pid varchar(3) , name varchar(10))
insert into tb values('001' , null  , '广东省')
insert into tb values('002' , '001' , '广州市')
insert into tb values('003' , '001' , '深圳市')
insert into tb values('004' , '002' , '天河区')
insert into tb values('005' , '003' , '罗湖区')
insert into tb values('006' , '003' , '福田区')
insert into tb values('007' , '003' , '宝安区')
insert into tb values('008' , '007' , '西乡镇')
insert into tb values('009' , '007' , '龙华镇')
insert into tb values('010' , '007' , '松岗镇')
go

--查询指定节点及其所有父节点的函数
create function f_pid(@id varchar(3)) returns @t_level table(id varchar(3))
as
begin
  insert into @t_level select @id
  select @id = pid from tb where id = @id and pid is not null
  while @@ROWCOUNT > 0
  begin
    insert into @t_level select @id 
    select @id = pid from tb where id = @id and pid is not null
  end
  return
end
go

--调用函数查询002(广州市)及其所有父节点
select a.* from tb a , f_pid('002') b where a.id = b.id order by a.id
/*
id   pid  name       
---- ---- ---------- 
001  NULL 广东省
002  001  广州市

（所影响的行数为 2 行）
*/

--调用函数查询003(深圳市)及其所有父节点
select