列的“HW_PART_NO”递归查询“CTE”锚和递归部分之间的类型不匹配。解决方案
日期：2014-05-18 浏览次数：20537 次
列的“HW_PART_NO”递归查询“CTE”锚和递归部分之间的类型不匹配。
求解决
报错
Types don't match between the anchor and the recursive part in column "HW_PART_NO" of recursive query "cte".
------解决方案--------------------
try:
求解决
- SQL code
;with cte as
(
select [SRV_PART_NO],
[HW_PART_NO]=substring(case when right([HW_PART_NO],1)=';' then [HW_PART_NO] else [HW_PART_NO]+';' end,1,charindex(';',case when right([HW_PART_NO],1)=';' then [HW_PART_NO] else [HW_PART_NO]+';' end)-1),
col3=stuff(case when right([HW_PART_NO],1)=';' then [HW_PART_NO] else [HW_PART_NO]+';' end,1,charindex(';',case when right([HW_PART_NO],1)=';' then [HW_PART_NO] else [HW_PART_NO]+';' end),'')
from win7_32
union all
select [SRV_PART_NO],[HW_PART_NO]=substring(col3,1,charindex(';',col3)-1),col3=stuff(col3,1,charindex(';',col3),'') from cte
where charindex(';',col3)>0
)
--insert into [Commdity Split] ([HW Part No],[HW_PART_NO])
select distinct [SRV_PART_NO],[HW_PART_NO] from cte
报错
Types don't match between the anchor and the recursive part in column "HW_PART_NO" of recursive query "cte".
------解决方案--------------------
try:
- SQL code
;with cte as
(
select [SRV_PART_NO],
[HW_PART_NO]=cast(substring(case when right([HW_PART_NO],1)=';' then [HW_PART_NO] else [HW_PART_NO]+';' end,1,charindex(';',case when right([HW_PART_NO],1)=';' then [HW_PART_NO] else [HW_PART_NO]+';' end)-1) as varchar(2000)),
col3=cast(stuff(case when right([HW_PART_NO],1)=';' then [HW_PART_NO] else [HW_PART_NO]+';' end,1,charindex(';',case when right([HW_PART_NO],1)=';' then [HW_PART_NO] else [HW_PART_NO]+';' end),'') as varchar(2000))
from win7_32
union all
select [SRV_PART_NO],[HW_PART_NO]=cast(substring(col3,1,charindex(';',col3)-1),col3=stuff(col3,1,charindex(';',col3),'') as varchar(2000)) from cte
where charindex(';',col3)>0
)
--insert into [Commdity Split] ([HW Part No],[HW_PART_NO])
select distinct [SRV_PART_NO],[HW_PART_NO] from cte
------解决方案--------------------
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