日期:2014-05-18  浏览次数:20397 次

求日期SQL
表原数据:
date num
------------------
2009-01-01 1
2009-01-02 10
2009-01-04 12
2009-01-08 20
2009-01-09 0
2009-01-10 1


我要出现查询结果是
date num
------------------
2009-01-01 1
2009-01-02 10
2009-01-03 0
2009-01-04 12
2009-01-05 0
2009-01-06 0
2009-01-07 0
2009-01-08 20
2009-01-09 0
2009-01-10 1
会出现跨月 年

------解决方案--------------------
生成一个日期表 A
A LEFT JOIN TB
------解决方案--------------------
master..spt_values构造时间表 与你的表left join
------解决方案--------------------
探讨

引用:
http://topic.csdn.net/u/20111101/16/7b219432-9f6d-45b8-81db-0456e242bfbe.html?83140

自己照着写

数据库不允许做这样的操作, 只能是查询, 建表是不可能让我怎么做的

------解决方案--------------------
对应的时间按你的要求自己修改一下

SQL code

use tempdb;
/*
create table A
(
    [date] date not null,
    [num] int
);
insert into A values
('2009-01-01',1),
('2009-01-02',10),
('2009-01-04',12),
('2009-01-08',20),
('2009-01-09',0),
('2009-01-10',1);
*/

declare @startdate datetime,@enddate datetime;
set @startdate='2009-01-01';
set @enddate='2009-01-31';
select B.day_time,ISNULL(A.num,0) as num from
(
select convert(varchar(10),dateadd(day,number,@startdate),120) as day_time
from
    master..spt_values 
where 
    datediff(day,dateadd(day,number,@startdate), @enddate)>=0
    and number>=0 
    and type='p'
) as B
left join A 
ON A.[date] = B.day_time;