日期:2014-05-18  浏览次数:20353 次

求SQL: 3表联合查询统计
表a:

ID NAME MONEY
1 车费 30
1 仓储费 500
2 搬运费 300

表b:

ID ITEM ACCOUNT
1 服务费 200
1 仓储费 500

表c:
ID Name
1 远航
2 英华


得到如下结果:

ID 客户 费用名称 应收 成本
 1 远航 服务费 200 0
  仓储费 500 500
  车费 0 30

合计毛利: 170


ID 客户 费用名称 应收 成本
 2 英华 搬运费 0 300

合计毛利: -300


------解决方案--------------------
select * from c inner join (select Id=(case when a.id=null then b.id else a.id end),Name=(case when a.Name=null then b.Item else a.Name end),Money=sum(a.Money),Account=Sum(b.Account) from a full outer join b a.id=b.id group by ID,Name) cc on c.id=cc.id
------解决方案--------------------
SQL code
--> 测试数据: #A
if object_id('tempdb.dbo.#A') is not null drop table #A
create table #A (ID int,NAME varchar(6),MONEY int)
insert into #A
select 1,'车费',30 union all
select 1,'仓储费',500 union all
select 2,'搬运费',300
--> 测试数据: #B
if object_id('tempdb.dbo.#B') is not null drop table #B
create table #B (ID int,ITEM varchar(6),ACCOUNT int)
insert into #B
select 1,'服务费',200 union all
select 1,'仓储费',500
--> 测试数据: #C
if object_id('tempdb.dbo.#C') is not null drop table #C
create table #C (ID int,Name varchar(4))
insert into #C
select 1,'远航' union all
select 2,'英华'


SELECT C.*,T.* FROM 
(
SELECT ID,NAME,SUM(应收)应收,SUM(成本) 成本, 0 AS RN 
 FROM 
(
SELECT ID ,NAME,0 AS 应收,MONEY AS 成本  FROM #A
UNION ALL
SELECT ID,ITEM,ACCOUNT,0 FROM #B
) T GROUP BY ID,NAME

UNION ALL

SELECT ID,'合计毛利',0, SUM(应收)-SUM(成本) AS 合计毛利 ,1 AS RN
 FROM 
(
SELECT ID ,NAME,0 AS 应收,MONEY AS 成本  FROM #A
UNION ALL
SELECT ID,ITEM,ACCOUNT,0 FROM #B
) T GROUP BY ID
) T,#C C WHERE T.ID=C.ID

ORDER BY T.ID,T.RN

/*
(所影响的行数为 3 行)


(所影响的行数为 2 行)


(所影响的行数为 2 行)

ID          Name ID          NAME     应收          成本          RN          
----------- ---- ----------- -------- ----------- ----------- ----------- 
1           远航   1           仓储费      500         500         0
1           远航   1           车费       0           30          0
1           远航   1           服务费      200         0           0
1           远航   1           合计毛利     0           170         1
2           英华   2           搬运费      0           300         0
2           英华   2           合计毛利     0           -300        1

(所影响的行数为 6 行)

------解决方案--------------------
SQL code
select c.id,c.name,tb.name,tb.money from c 
left join (select id,name,money from a union all select id,item,account from b) tb on c.id=tb.id

------解决方案--------------------
SQL code
---测试数据---
if object_id('[a]') is not null drop table [a]
go
create table [a]([ID] int,[NAME] varchar(6),[MONEY] int)
insert [a]
select 1,'车费',30 union all
select 1,'仓储费',500 union all
select 2,'搬运费',300
if object_id('[b]') is not null drop table [b]
go
create table [b]([ID] int,[ITEM] varchar(6),[ACCOUNT] int)
insert [b]
select 1,'服务费',200 union all
select 1,'仓储费',500
if object_id('[c]') is not null drop table [c]
go
create table [c]([ID] int,[Name] varchar(4))
insert [c]
select 1,'远航' union all
select 2,'英华'
 
---查询---
select 
  case when rn=1 then ltrim(ID) else '' end as ID,
  case when rn=1 then 客户 else '' end as 客户,
  费用名称,
  应收,
  成本
from(
select c.id,c.name as 客户,b.费用名称,
应收=sum(应收),
成本=sum(成本),
rn=row_number() over(partition by c.id order by getdate())
from c
left join
(
  select id,name as 费用名称,[money] as 应收,0 as 成本 from a 
  union all 
  select id,ITEM,0,[ACCOUNT] from b
) b
on c.id=b.id
group by c.id,c.name,b.费用名称
) t

---结果---
ID           客户   费用名称   应收          成本
------------ ---- ------ ----------- -----------
1            远航   仓储费    500         500
                  车费     30          0
                  服务费    0