日期:2014-05-18  浏览次数:20585 次

请问SQL中如何GROUP BY 与TOP
一个表中的数据

ID nickname addtime
1 a 2011-12-19 11:11:12
2 b 2011-12-19 11:11:12
1 c 2011-12-19 11:11:10
2 c 2011-12-19 11:11:10
1 a 2011-12-19 11:11:11
2 b 2011-12-19 11:11:11

需求是根据时间倒序,取出每个ID,nickname 的前两条数据。

------解决方案--------------------
SQL code
;
WITH    tmp
          AS ( SELECT   * ,
                        rn = ROW_NUMBER() OVER ( PARTITION BY id ORDER BY nickname )
               FROM     tb
             )
    SELECT  *
    FROM    tmp
    WHERE   rn <= 2

------解决方案--------------------
SQL code
select * from 
(select no=row_number() over(partition by id order by addtime desc),* from tb)t
 where no<3

------解决方案--------------------
SQL code
select 
  distinct b.*
from
  tb a
cross apply
  (select top 2 * from tb where id=a.id order by addtime desc)b