日期:2014-05-18  浏览次数:20553 次

分析一个汉字转化成拼音首字母的函数,经过测试,很好用
SQL code

ALTER FUNCTION [dbo].[GetPy](@Str   varchar(500)='')  
  returns   varchar(500)  
  as 
 
  begin  
      --定义变量
      declare   @strlen   int, @return   varchar(500), @ii   int  
      declare   @n   int, @c   char(1),@chn   nchar(1)  
       --设置初始值
      select   @strlen=len(@str),@return='',@ii=0  
      set   @ii=0  
      --开始循环取出没个字符
      while   @ii<@strlen  
      begin  
          select   @ii=@ii+1,@n=63,@chn=substring(@str,@ii,1)  
          if   @chn>'z'  
          select   @n   =   @n   +1  ,@c   =   case   chn   when   @chn   then   char(@n)   else   @c   end  
          from(  
              select   top   27   *  
              from(  
                  select   chn   =   '吖'  
                  union   all   select   '八'  
                  union   all   select   '嚓'  
                  union   all   select   '咑'  
                  union   all   select   '妸'  
                  union   all   select   '发'  
                  union   all   select   '旮'  
                  union   all   select   '铪'  
                  union   all   select   '丌' --because   have   no   'i'  
                  union   all   select   '丌'  
                  union   all   select   '咔'  
                  union   all   select   '垃'  
                  union   all   select   '嘸'  
                  union   all   select   '拏'  
                  union   all   select   '噢'  
                  union   all   select   '妑'  
                  union   all   select   '七'  
                  union   all   select   '呥'  
                  union   all   select   '仨'  
                  union   all   select   '他'  
                  union   all   select   '屲' --no   'u'  
                  union   all   select   '屲' --no   'v'  
                  union   all   select   '屲'  
                  union   all   select   '夕'  
                  union   all   select   '丫'  
                  union   all   select   '帀'  
                  union   all   select   @chn
              )   as   a  
              order   by   chn   COLLATE   Chinese_PRC_CI_AS    
          )   as   b  
          else   set   @c=@chn  
          set   @return=@return+@c  
      end  
      return(@return)  
  end  



------解决方案--------------------
恩 谢谢分享。
------解决方案--------------------
可惜不能区分多音字
------解决方案--------------------
谢谢分享
收藏
------解决方案--------------------
收藏
------解决方案--------------------
不知道怎么用啊?!
------解决方案--------------------
j9988写过

SQL code

create function fun_getPY(@str nvarchar(4000))
returns nvarchar(4000)
as
begin
declare @word nchar(1),@PY nvarchar(4000),@i int
set @PY=''
set @i=1
while (substring(@str,@i,1)<>'' or @i<=len(@str))
begin
set @word=substring(@str,@i,1)
--如果非汉字字符,返回原字符
set @PY=@PY+(case when unicode(@word) between 19968 and 19968+20901
then (select top 1 PY from (
select 'A' as PY,N'驁' as word
union all select 'B',N'簿'
union all select 'C',N'錯'
union all select 'D',N'鵽'
union all select 'E',N'樲'
union all select 'F',N'鰒'
union all select 'G',N'腂'
union all select 'H',N'夻'
union all select 'J',N'攈'
union all select 'K',N'穒'
union all select 'L',N'鱳'
union all select 'M',N'旀'
union all select 'N',N'桛'
union all select 'O',N'漚'
union all select 'P',N'曝'
union all select 'Q',N'囕'
union all select 'R',N'鶸'
union all select 'S',N'蜶'
union all select 'T',N'籜'
union all select 'W',N'鶩'
union all select 'X',N'鑂'
union all select 'Y',N'韻'
union all select 'Z',N'咗'
) T 
where word>=@word collate Chinese_PRC_CS_AS_KS_WS 
order by PY ASC) else @word end)
set @i=@i+1
end
return @PY
end


--函数调用实例:
select