日期:2014-05-18  浏览次数:20450 次

求一个存储过程或sql语句
SQL code
if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[monthlj]') and OBJECTPROPERTY(id, N'IsUserTable') = 1)
drop table [dbo].[monthlj]
GO

CREATE TABLE [dbo].[monthlj] (
    [采集日期] [varchar] (50) COLLATE Chinese_PRC_CI_AS NOT NULL ,
    [甲线煤量累计] [real] NULL ,
    [甲线石灰石累计] [real] NULL ,
    [甲线耗电量累计] [real] NULL ,
    [乙线煤量累计] [real] NULL ,
    [乙线石灰石累计] [real] NULL ,
    [乙线耗电量累计] [real] NULL ,
    [负荷1累计] [real] NULL ,
    [负荷2累计] [real] NULL ,
    [负荷3累计] [real] NULL 
) ON [PRIMARY]
GO

采集时间 数据如 20110927 20110928 20110929 20110930 20111001 
我想在一个页面选择年份 然后把所有这一年的每个月的 各个列的sum 列出来 
也就是说 选择2011年 以后,列表里显示的是 2011年一月到当前月的 所有列的 月累计
 

------解决方案--------------------
簡單舉個以年份查看的例子
SQL code

CREATE PROCEDURE p_monthlj_Year(
    @dt int
)
SELECT MONTH([采集日期]) AS 月份,
SUM([甲线煤量累计]) AS [甲线煤量累计],
............

FROM dbo].[monthlj] 
WHERE YEAR([采集日期])=@dt
GROUP BY MONTH([采集日期])

go
--調用
EXEC p_monthlj_Year 2011

------解决方案--------------------
探讨

采集日期 甲线煤量累计
20110928 21 23 25 31 33 35 41 43 45
20110929 675. 59.65287 57.43 1012.8 89.63 82.94 584.5 526.6 468.8
20110930 32.7 1254.83 9 60.24062 367.1203 101200 657
1000028 454.9 ……

------解决方案--------------------
SQL code
select 
left([采集日期],6) as 年月,
SUM(isnull([甲线煤量累计],0)) AS [甲线煤量累计],
SUM(isnull([甲线石灰石累计],0)) AS [甲线煤量累计],
...
SUM(isnull([负荷2累计],0)) AS [负荷2累计],
SUM(isnull([负荷3累计],0)) AS [负荷3累计]
from dbo].[monthlj] 
group by left([采集日期],6)
order by left([采集日期],6)

------解决方案--------------------
SQL code
select 
  sum(case datepart(mm,采集日期) when 1 then 甲线煤量累计 else 0 end) [甲线煤量累计_01月],
  sum(case datepart(mm,采集日期) when 2 then 甲线煤量累计 else 0 end) [甲线煤量累计_02月],
  ...
  sum(case datepart(mm,采集日期) when 12 then 甲线煤量累计 else 0 end) [甲线煤量累计_12月],
  如果还需要合计其他字段则如上写法即可。
from monthlj
where datepart(yy,采集日期) = 2011

------解决方案--------------------
SQL code

Select Convert(Varchar(7),采集日期,120) As 月份,
    Sum(isNull(甲线煤量累计,0)) As 甲线煤量累计,
    Sum(isNull(甲线石灰石累计,0)) As 甲线石灰石累计,
    Sum(isNull(甲线耗电量累计,0)) As 甲线耗电量累计,
    Sum(isNull(乙线煤量累计,0)) As 乙线煤量累计,
    Sum(isNull(乙线石灰石累计,0)) As 乙线石灰石累计,
    Sum(isNull(乙线耗电量累计,0)) As 乙线耗电量累计,
    Sum(isNull(负荷1累计,0)) As 负荷1累计,
    Sum(isNull(负荷2累计,0)) As 负荷2累计,
    Sum(isNull(负荷3累计,0)) As 负荷3累计
From monthlj
Where Convert(Varchar(4),采集日期,120) = '2011'
Group By Convert(Varchar(7),采集日期,120)

------解决方案--------------------
SQL code
select 
  sum(case when datepart(mm,采集日期)=1 then 甲线煤量累计 else 0 end) as '甲线煤量累计_01月',
  sum(case when datepart(mm,采集日期)=2 then 甲线煤量累计 else 0 end) as '甲线煤量累计_02月',
  ...
from
 monthlj
where
 datepart(yy,采集日期) = 2011