求SQL行列合併統計
item                       hdate
a 2006/01/02
b 2006/01/02
c 2006/01/03
d 2006/01/03
e 2006/01/03
f 2006/01/05
g 2006/01/06

==>

count item hdate
2 ab 2006/01/02
3 cde 2006/01/03
1 f 2006/01/05
1 g 2006/01/06          


------解决方案--------------------
create table T(item varchar(10), hdate datetime)
insert T select 'a ', '2006/01/02 '
union all select 'b ', '2006/01/02 '
union all select 'c ', '2006/01/03 '
union all select 'd ', '2006/01/03 '
union all select 'e ', '2006/01/03 '
union all select 'f ', '2006/01/05 '
union all select 'g ', '2006/01/06 '

create function fun(@hdate datetime)
returns varchar(100)
as
begin
declare @re varchar(100)
set @re= ' '
select @re=@re+item from T where hdate=@hdate

return @re
end

select num=count(*), itme=dbo.fun(hdate), hdate from T group by hdate

--result
num itme hdate
----------- ---------------------------------------------------------------- ------------------------------------------------------
2 ab 2006-01-02 00:00:00.000
3 cde 2006-01-03 00:00:00.000
1 f 2006-01-05 00:00:00.000
1 g 2006-01-06 00:00:00.000

(4 row(s) affected)
------解决方案--------------------
轻轻的我来了，正如我要轻轻的说：
。。。。。楼上正解~~