实现这样的字符串替换,有什么办法?
表中有一些类似操作日志的记录,如   
 select   *   from   customers   where   customerid= 'TCANG '   
 delete   from   orders   where   employeeid=9   
 insert   into   customers   values( 'AYWOT ', 'Pdodgtrwa   Ikuqyyayj,Onomkn   Jagerg ', 'Lgnuuf   Bjxjxg ', 'Pipzfb   Yczzkh   692 ', 'Iiyhgt ', 'NI ', '00328 ', 'Lbwywwd ', '57-8689-33306113 ')   
 update   orders   set   freight=009.91   where   orderid=17050   
 我想把它们中所有的具体值都替换成我所指定的一个字符串,如SOMEVALUE:   
 select   *   from   customers   where   customerid=SOMEVALUE   
 delete   from   orders   where   employeeid=SOMEVALUE   
 insert   into   customers   values(SOMEVALUE)   
 update   orders   set   freight=SOMEVALUE   where   orderid=SOMEVALUE   
 我打算用游标对每条这种记录做某个操作,达到这个目的。   
 有什么好的方案吗?   
 由于要替换的内容长度、位置都不确定,所以似乎有些复杂。
------解决方案--------------------没看懂。。。
------解决方案--------------------不太明白. 
------解决方案--------------------/* 
 我只写了替换等于的情况,其它情况楼主参照写: 
 */   
 declare @Test table (ha varchar(8000)) 
 insert @Test select  'select * from customers where customerid= ' 'TCANG ' ' ' 
 insert @Test select  'delete from orders where employeeid   = 9 ' 
 insert @Test select  'update orders set freight= 009.91 where orderid =17050 '   
 while exists (select 1 from @Test where charindex( ' = ', ha) >  0) update @Test set ha = replace(ha,  ' = ',  '= ') where charindex( ' = ', ha) >  0 
 while exists (select 1 from @Test where charindex( '=  ', ha) >  0) update @Test set ha = replace(ha,  '=  ',  '= ') where charindex( '=  ', ha) >  0 
 update @Test set ha = replace(ha,  '= ',  ' =  ') where charindex( '= ', ha) >  0 
 update @Test set ha = ha +  '  ' --这个空格很重要   
 declare @Replace varchar(100) 
 set @Replace =  'SOMEVALUE '   
 select * from @Test 
 /* 
 select * from customers where customerid =  'TCANG '  
 delete from orders where employeeid = 9  
 update orders set freight = 009.91 where orderid = 17050  
 */   
 while exists (select 1 from @Test where charindex( ' =  ', ha) >  0) update @Test set ha = stuff(ha, charindex( ' =  ', ha),charindex( '  ', ha, charindex( ' =  ', ha) + 3) - charindex( ' =  ', ha),  '= ' + @Replace) where charindex( ' =  ', ha) >  0 
 select * from @Test 
 /* 
 select * from customers where customerid=SOMEVALUE  
 delete from orders where employeeid=SOMEVALUE  
 update orders set freight=SOMEVALUE where orderid=SOMEVALUE  
 */ 
------解决方案--------------------为什么不考虑考虑正则实现呢?
------解决方案--------------------up