能在视图中建立索引的吧,如何创建?
能在视图中建立索引的吧,如何创建?   
 CREATE   VIEW   dbo.V_MemberLists      
 AS 
 SELECT   dbo.t_Member_Member.ID,   dbo.t_Member_Member.UserName,    
                   dbo.t_Member_Member.Name,   ISNULL(dbo.t_Member_Member.csMoney,   0)    
                   AS   csMoney,   ISNULL(dbo.t_Member_Member.getMoney,   0)   AS   getMoney,    
                   dbo.t_Member_Member.Code1,   dbo.t_Member_Member.CodeAll   AS   cCode,    
                   dbo.CheckStatusName(dbo.t_Member_Info.CheckStatus)   AS   CheckStatus,    
                   dbo.MemberStatusName(dbo.t_Member_Info.MemberStatus)   AS   MemberStatus,    
                   dbo.t_Member_Info.RegisterTime,   dbo.t_Member_Info.BeginTime,    
                   dbo.t_Member_Info.EndTime,   ISNULL(dbo.t_Member_Level.Name,    '无 ')    
                   AS   LevelName,   dbo.t_Member_Level.ID   AS   LevelID,    
                   dbo.t_Member_Level.ParentID 
 FROM   dbo.t_Member_Member   INNER   JOIN    
                   dbo.t_Member_Info   ON    
                   dbo.t_Member_Member.ID   =   dbo.t_Member_Info.MemberID   INNER   JOIN 
                   dbo.t_Member_Level   ON   dbo.t_Member_Info.LevelID   =   dbo.t_Member_Level.ID     
 创建索引时 
 create   unique   clustered   index   vname   on      V_MemberLists   
 但是提示如下: 
 无法在视图    'V_MemberLists '   上创建   索引,因为该视图未绑定到架构。 
------解决方案--------------------唯一索引不行,其他的可以,但是需要重新建立试图   
 CREATE VIEW dbo.V_MemberLists  
 WITH SCHEMABINDING                       --必须加这个 
 AS 
 SELECT dbo.t_Member_Member.ID, dbo.t_Member_Member.UserName,  
       dbo.t_Member_Member.Name, ISNULL(dbo.t_Member_Member.csMoney, 0)  
       AS csMoney, ISNULL(dbo.t_Member_Member.getMoney, 0) AS getMoney,  
       dbo.t_Member_Member.Code1, dbo.t_Member_Member.CodeAll AS cCode,  
       dbo.CheckStatusName(dbo.t_Member_Info.CheckStatus) AS CheckStatus,  
       dbo.MemberStatusName(dbo.t_Member_Info.MemberStatus) AS MemberStatus,  
       dbo.t_Member_Info.RegisterTime, dbo.t_Member_Info.BeginTime,  
       dbo.t_Member_Info.EndTime, ISNULL(dbo.t_Member_Level.Name,  '无 ')  
       AS LevelName, dbo.t_Member_Level.ID AS LevelID,  
       dbo.t_Member_Level.ParentID 
 FROM dbo.t_Member_Member INNER JOIN  
       dbo.t_Member_Info ON  
       dbo.t_Member_Member.ID = dbo.t_Member_Info.MemberID INNER JOIN 
       dbo.t_Member_Level ON dbo.t_Member_Info.LevelID = dbo.t_Member_Level.ID     
 go   
 create index vname on  V_MemberLists(字段列表) 
 go 
------解决方案--------------------帮助的文字,参考一下:   
 要建立索引的视图的名称。必须使用 SCHEMABINDING 定义视图才能在视图上创建索引。视图定义也必须具有确定性。如果选择列表中的所有表达式、WHERE 和 GROUP BY 子句都具有确定性,则视图也具有确定性。而且,所有键列必须是精确的。只有视图的非键列可能包含浮点表达式(使用 float 数据类型的表达式),而且 float 表达式不能在视图定义的其它任何位置使用。   
 若要在确定性视图中查找列,请使用 COLUMNPROPERTY 函数(IsDeterministic 属性)。该函数的 IsPrecise 属性可用来确定键列是否精确。   
 必须先为视图创建唯一的聚集索引,才能为该视图创建非聚集索引。    
 在 SQL Server 企业版或开发版中,查询优化器可使用索引视图加快查询的执行速度。要使优化程序考虑将该视图作为替换,并不需要在查询中引用该视图。