怎样改写这个SQL?
 select   sum(金额)as '出库金额 '   from 
 ( 
 select   isnull(sum((   c      *      k      *   (   h      /   1000)   *   7.85)      *      sl   *   dj),0.00)as   金额   from   t_kc   where   type= '板材 'and   status= '0 ' 
 union   all 
 select   isnull(sum(zl         *      c      *      sl   *   dj),0.00)   from   t_kc   where   type= '型材 'and   status= '0 ' 
 union   all 
 select   isnull(sum(sl   *   dj),0.00)   from   t_kc   where   type= '标准件 'and   status= '0 ' 
 union   all 
 select   isnull(sum(sl   *   dj),0.00)   from   t_kc   where      type= '消耗材料 'and   status= '0 '   
 )   a     
 go   
 select   sum(金额)as    '退库金额 '   from 
 ( 
 select   isnull(sum((   c      *      k      *   (   h      /   1000)   *   7.85)      *      sl   *   dj),0.00)as   金额   from   t_kc   where   type= '板材 'and   status= '2 ' 
 union   all 
 select   isnull(sum(zl         *      c      *      sl   *   dj),0.00)   from   t_kc   where   type= '型材 'and   status= '2 ' 
 union   all 
 select   isnull(sum(sl   *   dj),0.00)   from   t_kc   where   type= '标准件 'and   status= '2 ' 
 union   all 
 select   isnull(sum(sl   *   dj),0.00)   from   t_kc   where      type= '消耗材料 'and   status= '2 '   
 )   b   
 ------------------------------------   
 以上语句执行没有错误,但是执行结果是1列,2行记录,就是这样: 
 出库金额 
 1000 
 退库金额 
 400 
 -------------------------------------------- 
 我想得到这样的结果 
 出库金额               退库金额 
 1000                           4000 
 就是放到一个表内,一行2列.   
 该怎样做呢??谢谢大家.   
------解决方案--------------------  select sum(CASE status WHEN  '0 ' THEN 金额 ELSE 0 END) as  '出库金额 ', 
 sum(CASE status WHEN  '2 ' THEN 金额 ELSE 1 END) as  '退库金额 ' from 
 (   
 select isnull(sum(( c  *  k  * ( h  / 1000) * 7.85)  *  sl * dj),0.00)as 金额 from t_kc where type= '板材 'and status IN ( '0 ', '2 ') 
 union all 
 select isnull(sum(zl   *  c  *  sl * dj),0.00) from t_kc where type= '型材 'and status IN ( '0 ', '2 ') 
 union all 
 select isnull(sum(sl * dj),0.00) from t_kc where type= '标准件 'and status IN ( '0 ', '2 ') 
 union all 
 select isnull(sum(sl * dj),0.00) from t_kc where  type= '消耗材料 'and status IN ( '0 ', '2 ')   
 ) a 
------解决方案----------------------try   
 select [出库金额]= 
 ( 
 	select sum(金额)as '出库金额 ' from 
 	( 
 	select isnull(sum(( c  *  k  * ( h  / 1000) * 7.85)  *  sl * dj),0.00)as 金额 from t_kc where type= '板材 'and status= '0 ' 
 	union all 
 	select isnull(sum(zl   *  c  *  sl * dj),0.00) from t_kc where type= '型材 'and status= '0 ' 
 	union all 
 	select isnull(sum(sl * dj),0.00) from t_kc where typ