日期:2014-05-18  浏览次数:20594 次

关于批量排序取值的讨论
现有表A
create   table   a   (id   int,name   varchar(50),num   float)

insert   into   a(1, 'a ',0.1)
insert   into   a(2, 'a ',0.13)
insert   into   a(3, 'a ',0.06)
insert   into   a(4, 'a ',0.3)
insert   into   a(5, 'a ',0.58)
insert   into   a(6, 'a ',0.36)
....
insert   into   a(7, 'b ',0.11)
insert   into   a(8, 'b ',0.35)
insert   into   a(9, 'b ',0.16)
insert   into   a(10, 'b ',0.32)
insert   into   a(11, 'b ',0.78)
insert   into   a(12, 'b ',0.26)
....

要得到的结果
按name分组,得到排序的95%值
例如a
select   top   1   @value   =   tmp_value   from   (select   top   5   percent   num   as   tmp_value   from   a   where   name= 'a '   order   by   name   desc)   b order   by   name
现在要用一条语句获得a,b,....所有的对应的95%值,排除循环获取95%值,不知还有没有其它的方法,欢迎大家讨论!


------解决方案--------------------
select
t.*
from
a t
where
t.num in (select top 95 percent num from a where name=t.name order by num desc)
order by
t.name,t.num
------解决方案--------------------
select * from a where id in
(
select id=cast(id*0.95 as int) from
(
select id=max(id) from a group by name
)a
)