请高手帮忙解决这个问题。
题目是:(SQL)   Write   a   SQL   query   to   find   first   Week   Day   of   month.   
 这道题没给表,我怎么查询?
------解决方案--------------------      declare @ta table( date varchar(10)) 
 declare @startdate datetime 
 set @startdate= '2007-01-01 ' 
 while @startdate!>  '2007-12-01 ' 
 begin 
 insert @ta values(@startdate) 
 set @startdate=dateadd(month,1,@startdate) 
 end   
 declare @number int 
 set @number=7--星期日 
 select DATEADD(Day,7-(DATEPART(Weekday,a.date)+@@DATEFIRST-2)%7-1,a.date) as  '每个月份的第一个星期日 ' 
 from @ta a     
 每个月份的第一个星期日                                             
 ------------------------------------------------------  
 2007-01-07 00:00:00.000 
 2007-02-04 00:00:00.000 
 2007-03-04 00:00:00.000 
 2007-04-01 00:00:00.000 
 2007-05-06 00:00:00.000 
 2007-06-03 00:00:00.000 
 2007-07-01 00:00:00.000 
 2007-08-05 00:00:00.000 
 2007-09-02 00:00:00.000 
 2007-10-07 00:00:00.000 
 2007-11-04 00:00:00.000 
 2007-12-02 00:00:00.000   
 (所影响的行数为 12 行)   
------解决方案--------------------给你个思路吧,我用的SYBASE,不过也是T-SQL 
 Weekday的意思是非周六日的天,也就是平日的意思 
 在函数datepart(dw,s_day)的运用上,要注意你的系统是将哪天设置为一周的第一天,一般情况下是周日为第一天   
 select top 1000 getdate() as s_day,rowid=identity(5)  
   into #t1 
   from sysobjects   
 update #t1 set 
        s_day=dateadd(dd,rowid*(-1),s_day)   
 select convert(varchar(10),min(s_day),111) 
   from #t1 
 where datepart(dw,s_day) not in (1,7) 
 group by datepart(mm,s_day)