日期:2014-05-18 浏览次数:20718 次
分拆列值
原著:邹建
改编:爱新觉罗.毓华  2007-12-16  广东深圳
有表tb, 如下:
id          value
----------- -----------
1           aa,bb
2           aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id          value
----------- --------
1           aa
1           bb
2           aaa
2           bbb
2           ccc
1. 旧的解决方法(sql server 2000)
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b 
SELECT A.id, SUBSTRING(A.[values], B.id, CHARINDEX(',', A.[values] + ',', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(',' + A.[values], B.id, 1) = ','
DROP TABLE #
2. 新的解决方法(sql server 2005) 
create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go
SELECT A.id, B.value
FROM(
    SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
)A
OUTER APPLY(
    SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
)B
DROP TABLE tb
/*
id          value
----------- ------------------------------
1           aa
1           bb
2           aaa
2           bbb
2           ccc
(5 行受影响)
*/
------解决方案--------------------
create table tb(jg_dm varchar(20) , bz varchar(10))
insert into tb values('001,'        ,   '111') 
insert into tb values('001,002,'    ,   '125') 
insert into tb values('003,004,005,',   '达到') 
go 
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b 
select * from
(
  SELECT jg_dm = SUBSTRING(A.jg_dm, B.id, CHARINDEX(',', A.jg_dm + ',', B.id) - B.id) , A.bz
  FROM tb A, # B
  WHERE SUBSTRING(',' + A.jg_dm, B.id, 1) = ','
) t
where jg_dm <> ''
DROP TABLE #,tb
/*
jg_dm                bz         
-------------------- ---------- 
001                  111
001                  125
002                  125
003                  达到
004                  达到
005                  达到
(所影响的行数为 6 行)
*/
------解决方案--------------------