日期:2014-05-18 浏览次数:20728 次
--'12/26/1999'为参数
A. 计算 ISO 周的标量值用户定义函数
下例中,用户定义函数 ISOweek 取日期参数并计算 ISO 周数。为了正确计算该函数,必须在调用该函数前唤醒调用 SET DATEFIRST 1。 
CREATE FUNCTION ISOweek  (@DATE datetime)
RETURNS int
AS
BEGIN
   DECLARE @ISOweek int
   SET @ISOweek= DATEPART(wk,@DATE)+1
      -DATEPART(wk,CAST(DATEPART(yy,@DATE) as CHAR(4))+'0104')
--Special cases: Jan 1-3 may belong to the previous year
   IF (@ISOweek=0) 
      SET @ISOweek=dbo.ISOweek(CAST(DATEPART(yy,@DATE)-1 
         AS CHAR(4))+'12'+ CAST(24+DATEPART(DAY,@DATE) AS CHAR(2)))+1
--Special case: Dec 29-31 may belong to the next year
   IF ((DATEPART(mm,@DATE)=12) AND 
      ((DATEPART(dd,@DATE)-DATEPART(dw,@DATE))>= 28))
      SET @ISOweek=1
   RETURN(@ISOweek)
END
下面是函数调用。注意 DATEFIRST 设置为 1。
SET DATEFIRST 1
SELECT master.dbo.ISOweek('12/26/1999') AS 'ISO Week'
下面是结果集。
ISO Week
----------------
52