日期:2014-05-18  浏览次数:20846 次

如何去掉重复值的问题
关于循环担保的问题,数据如下:
客户 担保人
a b
b a
c d
d e
e c

检索二级循环担保的语句如下:
select table1.客户,table2.客户 from table table1, table table2 where table1.客户=table2.担保人
结果为两条:
a b
b a
这是两条重复记录,可以通过如下方式解决
select table1.客户,table2.客户 from table table1, table table2 where table1.客户=table2.担保人 and table1.客户 〉table2.客户



检索三级循环担保的结果为三条:
c d e
d e c
e c d
请问如何去掉这里的重复值

------解决方案--------------------
检索三级循环担保的结果为三条: 
c d e 
d e c 
e c d 
请问如何去掉这里的重复值

可否考虑写个函数,把三个字段合成一个串,然后逐一对串中每个字母排序生成一新串.这样就可以比较了吧.
------解决方案--------------------
只能通过函数来解决了。
------解决方案--------------------
函数和存储过程没什么大的区别,限制还特别多!
SQL code


create table b(ke varchar(5),dan varchar(5))
insert b
select 'a', 'b'
union all select 'b', 'a'
union all select 'c', 'd'
union all select 'd', 'e'
union all select 'e', 'c'

select 
    b1.ke,
    b2.ke,
    b3.ke 
from 
    b b1,
    b b2,
    b b3 
where 
    b1.dan =b2.ke 
and b2.dan<>b1.ke
and b2.dan=b3.ke 
and b3.dan<>b2.ke 
and b1.ke>b2.ke
----结果
e    c    d

------解决方案--------------------
刚才写了个递归函数感觉反而把问题弄复杂了,因为存在a,b--b,a这样的数据,清理后效率是很低的,所以就想到了对比字段上,可能不太好,见量!

create table b(ke varchar(5),dan varchar(5))
insert b
select 'a','b' union all
select 'b','a' union all
select 'c','d' union all
select 'd','e' union all
select 'e','c' union all
select '1','2' union all
select '2','1' union all
select '3','4' union all
select '4','5' union all
select '5','3'
union all
select '11','22' union all
select '22','33' union all
select '33','44' union all
select '44','11'

GO

--来得到合并的字符串的ASCII码的数字
CREATE FUNCTION F_UNIONTOTAL(@s VARCHAR(100))
RETURNS INT
AS
BEGIN
DECLARE @re INT
SELECT @s = RTRIM(LTRIM(@s)),@re = 0
WHILE @s<>''
BEGIN
SET @re = @re + ASCII(LEFT(@s,1))
SET @s = STUFF(@s,1,1,'')
END
RETURN @re
END
GO

--两级匹配
SELECT One,Two FROM
(
select One=Oa.ke,Two=Ob.ke,Three=dbo.F_UNIONTOTAL(Oa.ke+Ob.ke) 
from b Oa ,b Ob WHERE Oa.dan = Ob.ke
) A WHERE One + Two IN
(
SELECT Top 1 One+Two FROM
(
select One=Oa.ke,Two=Ob.ke,Three=dbo.F_UNIONTOTAL(Oa.ke+Ob.ke) 
from b Oa ,b Ob WHERE Oa.dan = Ob.ke
) B WHERE A.Three = B.Three
)

--三级匹配
SELECT One,Two,Three FROM 
(
select One=Oa.ke,Two=Oa.dan,Three=Ob.dan,Four=dbo.F_UNIONTOTAL(Oa.ke+Oa.dan+Ob.dan)
from b Oa ,b Ob WHERE Oa.dan = Ob.ke AND dbo.F_UNIONTOTAL(Oa.ke+Oa.dan) <> dbo.F_UNIONTOTAL(Ob.ke+Ob.dan)
) A WHERE One + Two + Three IN
(
SELECT TOP 1 One + Two + Three FROM 
(
select One=Oa.ke,Two=Oa.dan,Three=Ob.dan,Four=dbo.F_UNIONTOTAL(Oa.ke+Oa.dan+Ob.dan)
from b Oa ,b Ob WHERE Oa.dan = Ob.ke AND dbo.F_UNIONTOTAL(Oa.ke+Oa.dan) <> dbo.F_UNIONTOTAL(Ob.ke+Ob.dan)
) B WHERE A.Four = B.Four 




DROP FUNCTION F_UNIONTOTAL
DROP TABLE b



One Two
----- ----- 
11 22
2 1
3 4
33 44
4 5
44 11
5 3
b a
c d
d e
e c

(所影响的行数为 11 行)

One Two Three 
----- ----- ----- 
e c d
5 3 4
22 33 44
33 44 11
44 11 22

(所影响的行数为 5 行)