知道表名怎么枚举出它的各个字段名?
rt:知道表名怎么枚举出它的各个字段名?

请看清意思~

------解决方案--------------------
select * from sysobjects where id=object_id( '表名 ')
------解决方案--------------------
sysobjects为查表名
syscolumns为查列名


------解决方案--------------------
查出表的各个字段的所有属性

SELECT
表名 = case when a.colorder=1 then d.name else ' ' end,
表说明 = case when a.colorder=1 then isnull(f.value, ' ') else ' ' end,
字段序号 = a.colorder,
字段名 = a.name,
标识 = case when COLUMNPROPERTY( a.id,a.name, 'IsIdentity ')=1 then '√ 'else ' ' end,
主键 = case when exists(SELECT 1 FROM sysobjects where xtype= 'PK ' and parent_obj=a.id and name in (
SELECT name FROM sysindexes WHERE indid in(
SELECT indid FROM sysindexkeys WHERE id = a.id AND colid=a.colid))) then '√ ' else ' ' end,
类型 = b.name,
占用字节数 = a.length,
长度 = COLUMNPROPERTY(a.id,a.name, 'PRECISION '),
小数位数 = isnull(COLUMNPROPERTY(a.id,a.name, 'Scale '),0),
允许空 = case when a.isnullable=1 then '√ 'else ' ' end,
默认值 = isnull(e.text, ' '),
字段说明 = isnull(g.[value], ' ')
FROM
syscolumns a
left join
systypes b
on
a.xusertype=b.xusertype
inner join
sysobjects d
on
a.id=d.id and d.xtype= 'U ' and d.name <> 'dtproperties '
left join
syscomments e
on
a.cdefault=e.id
left join
sysproperties g
on
a.id=g.id and a.colid=g.smallid
left join
sysproperties f
on
d.id=f.id and f.smallid=0
where
d.name= '要查询的表 ' --如果只查询指定表,加上此条件
order by
a.id,a.colorder

------解决方案--------------------
--sql 2005
select name from sys.columns where object_id=object_id( 'b ')
order by column_id
------解决方案--------------------
object_id( '表名 ') 返回数据库对象标识号。