请教一个数据过滤的问题，请指教.
表tb1有列field1，有如下数据：
field1
101-123-5
101-123
101-200
101-200-1-100
101-200-2
101-300
101-300-1
101-400-1-100-B

我想取出如下数据:
field1
101-123
101-200
101-300
101-400-1-100-B
即，相同代码中取最短的一个

请问有什么好的方法吗？想了好久了，谢谢各位朋友！

------解决方案--------------------
declare @t table(code varchar(30))
insert into @t select '101-123-5 '
insert into @t select '101-123 '
insert into @t select '101-200 '
insert into @t select '101-200-1-100 '
insert into @t select '101-200-2 '
insert into @t select '101-300 '
insert into @t select '101-300-1 '
insert into @t select '101-400-1-100-B '

select
t.*
from
@t t
where
not exists(select 1 from @t where t.code like code+ '% ' and len(code) <len(t.code))
------解决方案--------------------
Select * From tb1 A
Where Not Exists (Select * From tb1 Where A.field1 Like '% ' + field1 + '% ' And A.field1 != field1)
------解决方案--------------------
declare @t table(code varchar(30))
insert into @t select '101-123-5 '
insert into @t select '101-123 '
insert into @t select '101-200 '
insert into @t select '101-200-1-100 '
insert into @t select '101-200-2 '
insert into @t select '101-300 '
insert into @t select '101-300-1 '
insert into @t select '101-400-1-100-B '

select
t.*
from
@t t
where
not exists(select 1 from @t where t.code like code+ '% ' and code <t.code)