如何查询相同的记录?
表格如下: 
 id   num1   num2   num3 
 1         1            3               2 
 2         2            2               1 
 3         2            1               1 
 4         1            1               2 
 5         2            2               2 
 6         3            3               1 
 7         2            2               1 
 ..      ..         ..            ..   
 想查询相同num1/num2/num3的记录: 
 如   id   2和id   7 
------解决方案--------------------select * from 表 t where exists(select 1 from 表 where id <> t.id and num1=t.num1 and num2=t.num2 and num3=t.num3)
------解决方案--------------------SELECT DISTINCT A.* FROM TABLE A INNER JOIN TABLE B ON A.ID <> B.ID AND A.num1=B.num1  AND A.num2=B.num2 AND A.num3=B.num3 
 或者 
 SELECT DISTINCT A.* FROM TABLE A INNER JOIN TABLE B ON A.ID <> B.ID  
 CAST(ISNULL(A.num1,0) AS VARCHAR(50))+CAST(ISNULL(A.num2,0) AS VARCHAR(50))+CAST(ISNULL(A.num3,0) AS VARCHAR(50))=CAST(ISNULL(B.num1,0) AS VARCHAR(50))+CAST(ISNULL(B.num2,0) AS VARCHAR(50))+CAST(ISNULL(B.num3,0) AS VARCHAR(50))
------解决方案--------------------SELECT * 
 FROM Table1 
 WHERE convert(varchar(10),num1)+ ', '+convert(varchar(10),num2)+ ', '+convert(varchar(10),num3)  
 IN (SELECT convert(varchar(10),num1)+ ', '+convert(varchar(10),num2)+ ', '+convert(varchar(10),num3) FROM Table1 GROUP BY num1,num2,num3 having count(*)> 1)
------解决方案--------------------  select * from T as tmp 
 where (select count(*) from T where num1=tmp.num1 and num2=tmp.num2 and num3=tmp.num3)> 1