日期:2014-5-19 浏览次数:20338次

如何查漏编号字段
SQL code


我有一张表A,有字段A(编号,插入一行编号+1),字段B(金额),字段C(人次)

现在想统计一段数据:select count(1) from 表A where 字段A>=200 and 字段A<=400
结果是199张,漏了一个编号,想用一个查询语句查出漏的编号是那个号?或者漏的编号的上一个编号



------解决方案--------------------
--参考
SQL code
 SELECT Col1+1 AS 缺号起点,
          (SELECT MIN(Col1) FROM tb
WHERE Col1>t.Col1) -1 AS 缺号终点
 FROM tb AS t
 WHERE NOT EXISTS
(SELECT * FROM tb WHERE Col1=t.Col1+1)

------解决方案--------------------
假设只有三位数字。
那么可以用如下代码:

SQL code
SELECT 字段1 
from LI T
where not exists (select 1 From LI 
                  where (Cast(right(字段1,3) as int)  -  cast(right(T.字段1,3) as int))  = 1)

------解决方案--------------------
SQL code
--生成已用编号分布字符串的函数    
CREATE FUNCTION f_GetStrSeries(@col1 varchar(10))   
RETURNS varchar(8000)   
AS   
BEGIN   
    DECLARE @re varchar(8000),@pid int   
    SELECT @re='',@pid=-1   
    SELECT @re=CASE    
            WHEN col2=@pid+1 THEN @re   
            ELSE @re   
                +CASE    
                    WHEN RIGHT(@re,CHARINDEX(',',REVERSE(@re)+',')-1)=@pid THEN ''   
                    ELSE CAST(-@pid as varchar)   
                END   
                +','+CAST(col2 as varchar)    
            END,   
        @pid=col2   
    FROM tb   
    WHERE col1=@col1   
    ORDER BY col2   
    RETURN(STUFF(@re,1,2,'')   
        +CASE    
            WHEN RIGHT(@re,CHARINDEX(',',REVERSE(@re)+',')-1)=@pid THEN ''   
            ELSE CAST(-@pid as varchar)   
        END)   
END   
GO   
   
--生成缺号分布字符串的函数    
CREATE FUNCTION f_GetStrNSeries(@col1 varchar(10))   
RETURNS VARCHAR(8000)   
AS   
BEGIN   
    DECLARE @re varchar(8000),@pid int   
    SELECT @re='',@pid=0   
    SELECT @re=CASE    
            WHEN col2=@pid+1 THEN @re   
            ELSE @re+','+CAST(@pid+1 as varchar)   
                +CASE    
                    WHEN @pid+1=col2-1 THEN ''   
                    ELSE CAST(1-col2 as varchar)   
                END   
            END,   
        @pid=col2   
    FROM tb   
    WHERE col1=@col1   
    ORDER BY col2   
    RETURN(STUFF(@re,1,1,''))   
END   
GO   
   
--调用测试    
--测试数据    
CREATE TABLE tb(col1 varchar(10),col2 int)   
INSERT tb SELECT 'a',2   
UNION ALL SELECT 'a',3   
UNION ALL SELECT 'a',5   
UNION ALL SELECT 'a',8   
UNION ALL SELECT 'a',9   
UNION ALL SELECT 'b',1   
UNION ALL SELECT 'b',5   
UNION ALL SELECT 'b',6   
UNION ALL SELECT 'b',7   
   
--查询    
SELECT col1,   
    col2_Series=dbo.f_GetStrSeries(col1),   
    col2_Series=dbo.f_GetStrNSeries(col1)   
FROM tb   
GROUP BY col1   
/*--结果    
col1       col2_Series       col2_Series    
-------------- ------------------------ --------------    
a          2-3,5,8-9        1,4,6-7   
b          1,5-7           2-4   
--*/   

--生成已用编号分布字符串的函数 
CREATE FUNCTION f_GetStrSeries(@col1 varchar(10)) 
RETURNS varchar(8000) 
AS 
BEGIN 
    DECLARE @re varchar(8000),@pid int 
    SELECT @re='',@pid=-1 
    SELECT @re=CASE  
            WHEN col2=@pid+1 THEN @re 
            ELSE @re 
                +CASE  
                    WHEN RIGHT(@re,CHARINDEX(',',REVERSE(@re)+',')-1)=@pid THEN '' 
                    ELSE CAST(-@pid as varchar) 
                END 
                +','+CAST(col2 as varchar)  
            END, 
        @pid=col2 
    FROM tb 
    WHERE col1=@col1 
    ORDER BY col2 
    RETURN(STUFF(@re,1,2,'') 
        +CASE  
            WHEN RIGHT(@re,CHARINDEX(',',REVERSE(@re)+',')-1)=@pid THEN '' 
            ELSE CAST(-@pid as varchar) 
        END) 
END 
GO 
 
--生成缺号分布字符串的函数 
CREATE FUNCTION f_GetStrNSeries(@col1 varchar(10)) 
RETURNS VARCHAR(8000) 
AS 
BEGIN 
    DECLARE @re varchar(8000),@pid int 
    SELECT @re='',@pid=0 
    SELECT @re=CASE